Which of the following scatterplots represents the data shown below? (1, 31), (2, 8), (3, 38), (4, 14), (5, 22), (6, 31), (7, 27
1 answer:
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Answer:
about 2949 feet
Step-by-step explanation:
The geometry of the situation can be modeled by a right triangle. The height of the cliff can be taken to be the side opposite the given angle, and the distance to the coyote will be the side adjacent to the given angle. The relation between these values is the trig function ...
Tan = Opposite/Adjacent
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<h3>setup</h3>Filling in the known values, we have ...
tan(6°) = (310 ft)/(distance to coyote)
<h3>solution</h3>Multiplying by (distance to coyote)/tan(6°) gives ...
distance to coyote = (310 ft)/tan(6°) ≈ 310/0.105104 ft
distance to coyote ≈ 2949.453 ft
The coyote is about 2949 feet from the base of the cliff.
The answer is 42.
The question is asking for angle N. We know from the question that angle N is equal to angle E (Don't think about the scale factor because it only applies to the sides. They're just trying to trick you).
To find angle E:
Move numbers to the right side:
Combine like terms:
Divide both sides by 13:
The formula for angle E:
Plug in the 8:
The angle measure of E is 42. So angle N is automatically 42 too.
To solidify, we can try to use the formula which they give us for angle N:
The question is asking for angle N. We know from the question that angle N is equal to angle E (Don't think about the scale factor because it only applies to the sides. They're just trying to trick you).
To find angle E:
Move numbers to the right side:
Combine like terms:
Divide both sides by 13:
The formula for angle E:
Plug in the 8:
The angle measure of E is 42. So angle N is automatically 42 too.
To solidify, we can try to use the formula which they give us for angle N: