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2 years ago

6

(3x-1)(ax+b) = 12x² - 19x + cWork out the values of a, b and c.

1 answer:

Snezhnost [94]2 years ago

4 0

The value of a, b, c is
a=4
b= -5
c= 5

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What is the greatest common factor of 30, 48, and 2?

arlik [135]

Answer:

<h3>The greatest common factor of 30, 48 and 2 is 2</h3>

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2 years ago

Prime numbers less than 50

SVETLANKA909090 [29]

Answer:

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Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

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Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

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$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

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therefore

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$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

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<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

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$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

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$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

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Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

so

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

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$cos(\alpha)=\frac{\sqrt{33}}{7}$

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3 years ago

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frosja888 [35]

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3 years ago

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