What is the volume of a cylinder with base radius 2 and height 9?

It is assumed that the mean weight of a Labrador retriever is 70 pounds. A breeder claims that the average weight of an adult ma

Sindrei [870]

Answer:

z(s) is in the acceptance region we accept H₀. We don´t have enough evidence to support the breeder´s claim

Step-by-step explanation:

We will test the breeder´s claim at 95% ( CI) or significance level

α = 5 % α = 0,05 α /2 = 0,025

Sample Information:

sample size n = 45

sample mean x = 72,5 pounds

Sample standard deviation s = 16,1

1.-Hypothesis Test:

Null Hypothesis H₀ x = 70

Alternative Hypothesis Hₐ x ≠ 70

Alternative hypothesis contains the information about what kind of test has to be developed ( in this case it will be a two-tail tets)

2.-z (c) is from z-table z(c) = 1,96

3.- z(s) = ( x - 70 ) / 16,1 / √45

z(s) = (72,5 -70 ) *√45 / 16,1

z(s) = 2,5 * 6,71 / 16,1

z(s) = 1,04

4.-Comparing z(s) and z(c)

z(s) < z(c)

Then z(s) is in the acceptance region we accept H₀. We don´t have enough evidence to support the breeder´s claim

7 0

3 years ago

Read 2 more answers

Please please someone help

natka813 [3]

The answer is the first one:

bc its not growing by a (-)1/2 and the 3rd one just doesnt make sense

7 0

3 years ago

Read 2 more answers

If sqaure root x = 9, then x is between _____. 15 and 20 2 and 3 80 and 90 4 and 5

kolbaska11 [484]

If sqrt x = 9 then x = 9*9 = 81

Answer is between 80 and 90.

3 0

3 years ago

Read 2 more answers

10 1/2 * 10 1/2 simplify

Marta_Voda [28]

$\frac{441}{4}$

change the mixed numbers to improper fractions and multiply the numerators / denominators

10 $\frac{1}{2}$ = $\frac{21}{2}$

$\frac{21}{2}$ × $\frac{21}{2}$ = $\frac{441}{4}$ = 1110 $\frac{1}{4}$

4 0

3 years ago

A data set of 27 different numbers has a mean of 33 and a median of 33. A new data set is

Svetllana [295]

Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

The median is the value in the middle, and the mean is calculated as:

$M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}$

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k" (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

Now we add 7 to all the values greater than the median

We subtract 7 to all values smaller than the median.

Then the median remains unchanged (because we did not add nor subtract anything to the median).

The new mean will be:

$M' = \frac{(x_1 - 7) + (x_2 - 7) + ... + (x_{k}) + ... + (x_n + 7)}{N} = \frac{(x_1 + x_2 + ... + x_n) + (-7)*(n/2 - 0.5) + 7*(n/2 - 0.5)}{N} = \frac{(x_1 + x_2 + ... + x_n)}{N} = M$

So the mean does not change.

Because the mean is computed as the sum of the numbers divided by N, and the mean does not change, and N does not change, then the sum of the numbers does not change.

Finally, the standard deviation is computed as:

$SD = \sqrt{\frac{(x_1 - M)^2 + ... + (xn - M)^2}{N} }$

Because M does not change, if we add or subtract numbers to some of the values, the standard deviation will change (Because all the terms are squared, so the added and subtracted sevens don't cancel like in the previous cases)

Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

6 0

2 years ago

What is the volume of a cylinder with base radius 2 and height 9?​

What is the volume of a cylinder with base radius 2 and height 9?