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-BARSIC- [3]
3 years ago
13

What is the scale factor from triangle abc to triangle A' B' C' ? Also explain how.​

Mathematics
2 answers:
Serga [27]3 years ago
5 0
Okay so 938 and 909 are the main triangle in algebra 2. This is because
stiv31 [10]3 years ago
5 0
Answer: Possibly 1.33333333 or rounded to 1.33

Explanation: Length AB multiplied by 1.33333333 equals 4, which is the length of A’B’.

Length BC multiplied by 1.33333333 equals 5.3333332, which is close to the length of B’C’
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A/m=4g-h <br>need help with this problem ​
Olegator [25]

Answer:

a= m*(4g-h)

Step-by-step explanation:

hope it helps you

4 0
3 years ago
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Help pleaseee :)!!!!!!!!!
harkovskaia [24]

Answer:

5x/x+3

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask!

3 0
3 years ago
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Part 2 of the last question I asked​
Sedaia [141]

7. Answer:  +4,      x ≥ 16

<u>Step-by-step explanation:</u>

x - 4 ≥ 12

Add 4 to both sides (to isolate the variable):

x - 4 <u>+ 4</u> ≥ 12 <u>+ 4</u>

x             ≥ 16

Graph has a closed dot with an arrow pointing to the right of 16.

16 ·------------→

9. Answer:  x ≤ 9

<u>Step-by-step explanation:</u>

x - 20 ≤ -11

Add 20 to both sides of the equation:

x -20 +20  ≤ -11 +20

x                 ≤ 9

Graph has a closed dot with an arrow pointing to the left of 9.

←----------· 9

5 0
4 years ago
An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
Strike441 [17]
<h2>Answer with explanation:</h2>

Given : An urn contains 2 red marbles and 3 blue marbles.

Total marbles = 2+3=5

a) The general ways in which the person could get a red marble and a blue marble are :

1)  He draws red marble first and then second marble as blue.

2)  He draws blue marble first marble and then second marble as red.

b)  The number of ways to get one red and one blue marble is given by :-

^2C_1\times^3C_1=2\times3=6                          (i)

c) Number of ways to get 2 marbles from 5 is given by :-

^5C_2=\dfrac{5!}{2!(5-2)!}=\dfrac{5\times4\times3!}{3!\times2}=10     (ii)

Now, The probability the person gets a red and a blue marble will be :-

P(R\ \&B)=\dfrac{6}{10}=0.6       [Divide (i) by (ii)]

Hence, the  probability the person gets a red and a blue marble= 0.6

5 0
4 years ago
Simplify |−19+9|/3−|14−22|/9.
aliina [53]

Answer:

2¾

Step-by-step explanation:

\\  \sf \frac{ | - 19 + 9| }{3}  -  \frac{ |14 - 22| }{9}

\\  \sf =  \frac{ | - 10| }{3}  -  \frac{ | - 8| }{9}

\\  \sf =  \frac{10}{3}  -  \frac{8}{9}

\\  \sf =  \frac{30 - 8}{9}

\\  \sf =  \frac{22}{8}

\\  \sf =  \frac{11}{4}

\\  \sf =  2 \frac{3}{4}

6 0
3 years ago
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