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Stels [109]
3 years ago
14

An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th

em. a) State the general ways in which the person could get a red marble and a blue marble b) State the number of ways this can occur. c) What is the probability the person gets a red and a blue marble? P(R & B) =
Mathematics
1 answer:
Strike441 [17]3 years ago
5 0
<h2>Answer with explanation:</h2>

Given : An urn contains 2 red marbles and 3 blue marbles.

Total marbles = 2+3=5

a) The general ways in which the person could get a red marble and a blue marble are :

1)  He draws red marble first and then second marble as blue.

2)  He draws blue marble first marble and then second marble as red.

b)  The number of ways to get one red and one blue marble is given by :-

^2C_1\times^3C_1=2\times3=6                          (i)

c) Number of ways to get 2 marbles from 5 is given by :-

^5C_2=\dfrac{5!}{2!(5-2)!}=\dfrac{5\times4\times3!}{3!\times2}=10     (ii)

Now, The probability the person gets a red and a blue marble will be :-

P(R\ \&B)=\dfrac{6}{10}=0.6       [Divide (i) by (ii)]

Hence, the  probability the person gets a red and a blue marble= 0.6

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Have a wonderful day!  :)

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Read 2 more answers
the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width
-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.  

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

Hence length and width of rectangle is 15 inches and 6 inches.

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3 years ago
What is the name for numbers that are greater than zero
grigory [225]

Those are positive numbers.

Those that are less than zero are called negative numbers.

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Answer:

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Step-by-step explanation:

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Take the derivative

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Step-by-step explanation:

you need to add 808 plus 808 which is 1616 then add 340 plus 340 which is 680, then subtract 1616-680 which is 976.

8 0
3 years ago
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