Question

Help with this math problem

Answer 1

${a}^{2} + {b}^{2} = {c}^{2} \\ ({ \sqrt{47} })^{2} + {b}^{2} = ({10)}^{2} \\ 47 + {b}^{2} = 100 \\ {b}^{2} = 100 - 47 \\ {b}^{2} = 53 \\ b = \sqrt{53}$

_o_o_

cos k = adjacent / hypotenuse

$\cos(k) = \frac{ \sqrt{53} }{10}$

I hope I helped you^_^