Question

Enter the equation of the line in any format that we have learned that passes the two points: (2, -5) and (0, 1).

Answer 1

Given points:

• (2, -5) and (0, 1)

Find the slope:

• m = (1 - (-5))/(0 - 2) = 6/(-2) = -3

Point - slope form:

• y - (-5) = -3(x - 2) ⇒ y + 5 = -3(x - 2)

Convert into slope- intercept form:

• y = -3x + 6 - 5 ⇒ y = -3x + 1

Convert into standard form:

• 3x + y = 1

Answer 2

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

let's find slope (m) :

• $\dfrac{y2 - y1}{x2 - x1}$

• $\dfrac{1 - ( - 5)}{0 - 2}$

• $\dfrac{6}{ - 2}$

• $- 3$

Plugging value of x and y from point (0 , 1) and slope (m) = -3, in general equation of line we will get the value of y - intercept (c)

that is :

• $y = mx + c$

• $1 = (0 \times - 3) + c$

• $c = 1$

y intercept (c) = 1, now let's plug the value of slope(m) and y - intercept (c) in general equation of line to get the required equation of line which passes from given two points.

• $y = - 3x + 1$