Write (9 +6/) - (1 + 3/) as a complex number in standard form.

Mathematics

1 answer:

kirza4 [7]3 years ago

8 0

I'm assuming the given problem is (9+6i) - (1+3i)

If that assumption is true, then this is what the steps look like

(9+6i) - (1+3i)

9+6i - 1-3i

(9-1)+(6i-3i)

(9-1)+(6-3)i

8+3i

<h3>Answer: 8+3i</h3>

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mylen [45]

Given that a polynomial function P(x) has rational coefficients.

Two roots are already given which are i and 7+8i,

Now we have to find two additional roots of P(x)=0

Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.

conjugate of a+bi is given by a-bi

So using that logic, conjugate of i is i

also conjugate of 7+8i is 7-8i

Hence final answer for the remaining roots are (-i) and (7-8i).

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3 years ago

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nadya68 [22]

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The rest is below