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Rudiy27
2 years ago
12

two speedboats leave the dock at the same time and travel in opposite directions. one travels 9 mi/hr faster than the other. Aft

er 2 hr the boats are 170 mi apart. How fast is each boat travelling ?
Mathematics
1 answer:
Likurg_2 [28]2 years ago
6 0

Answer: \frac{170}{X}+\frac{170}{X-9}=2

(=)17 0x +170x+1530=2x²+18x

(=)-2 x² +322x+1530=0

Δ=b²-4ac

Δ=115924

\sqrt{}Δ=340,476>0

because Δ>0 so that 2 X

=>x₁=2 (true), x₂=-161(false)

X+9= 2+9=11

first travel 2 mi/hr

second travel 11 mi/hr

Step-by-step explanation:

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Can someone help me with translation
Arte-miy333 [17]

Answer:

  P' = (4, 4)

Step-by-step explanation:

T(x, y) is a function of x and y. Put the x- and y-values of point P into the translation formula and do the arithmetic.

  P' = T(8, -3) = (8 -4, -3 +7) = (4, 4)

_____

<em>Comment on notation</em>

The notation can be a little confusing, as the same form is used to mean different things. Here, P(8, -3) means <em>point P</em> has coordinates x=8, y=-3. The same form is used to define the translation function:

  T(x, y) = (x -4, y+7)

In this case, T(x, y) is not point T, but is <em>a function named T</em> (for "translation function") that takes arguments x and y and gives a coordinate pair as a result.

3 0
3 years ago
What is the equation of the line that passes through the point (4,3) and has an undefined slope?
wariber [46]

x = 4

A line with an undefined slope is a vertical line parallel to the y-axis and passing through all points with the same x-coordinate. For this reason it's equation is x = c where c is the value of the x-coordinate it passes through.

line passes through (4, 3 )

Hence equation is x = 4


6 0
2 years ago
Please help asap 25 pts
Usimov [2.4K]

(22,12) m=4

y=mx+b

12=4*22+b

12=88+b

subtract 88 from each side

b=-76

y = 4x-76

subtract 4x from each side

-4x+7 = -76

Choice A


4 0
3 years ago
Find the x-coordinates where f ' (x)=0 for f(x)=2x+sin(4x) in the interval [0, pi]
MAVERICK [17]

Answer:

The x-coordinate is \dfrac{\pi}{6}[/tex].

Step-by-step explanation:

We are given a function f(x) as:

f(x)=2x+\sin (4x)

Now on differentiating both side with respect to x we get that:

f'(x)=2+4 \cos (4x)

When f'(x)=0

this means that 2+4\cos (4x)=0\\\\4\cos (4x)=-2\\\\\cos(4x)=\dfrac{-1}{2}

Hence, cosine function takes the negative value in second and third quadrant but we have to only find the value in the interval [0,\pi].

also we know that \cos (\dfrac{2\pi}{3})=\dfrac{-1}{2}----(1) (which lie in the second quadrant)

so on comparing our equation with equation (1) we obtain:

4x=\dfrac{2\pi}{3}\\\\x=\dfrac{\pi}{6}

Hence, the x-coordinates where f'(x)=0 for f(x)=2x+\sin(4x) is \dfrac{\pi}{6}.

5 0
3 years ago
What is the value of exppresion if m=3 and n=2 (2m)3 +3(6-n)n?
shtirl [24]

Answer:

102

Step-by-step explanation:

2(3)³ + 3(6-2)2

2 (27) + 3(4)2

54 + 48

102

7 0
3 years ago
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