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oksano4ka [1.4K]
3 years ago
9

Match the following items help me plz ASAP

Mathematics
2 answers:
irina [24]3 years ago
8 0
1 proper fraction (fraction is normal)
2 mixed number example 1.5 of a cup it’s not a even number
3 equivalent fraction because it’s a whole number (3/3 = 1)
4 improper fraction (36/2)
5 denominator (_/this)
6 numerator (this/_)
Y_Kistochka [10]3 years ago
3 0
1. Proper Fraction
2. Mixed Number
3. Equivalent Fractions
4. Improper Fraction
5. Denominator
6. Numerator
This should help.
You might be interested in
9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?
SSSSS [86.1K]

Answer:

Part 4) r=84\ units

Part 9) sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) sin(\theta)=-\frac{9\sqrt{202}}{202}

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

C=2\pi r

using proportion

\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}

simplify

\frac{r}{180^o}=\frac{56}{120^o}

solve for r

r=\frac{56}{120^o}(180^o)

r=84\ units

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

cos^2(\theta)+sin^2(\theta)=1

we have

cos(\theta)=-\frac{2}{3}

substitute the given value

(-\frac{2}{3})^2+sin^2(\theta)=1

\frac{4}{9}+sin^2(\theta)=1

sin^2(\theta)=1-\frac{4}{9}

sin^2(\theta)=\frac{5}{9}

square root both sides

sin(\theta)=\pm\frac{\sqrt{5}}{3}

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?    

see the attached figure to better understand the problem

In the right triangle ABC of the figure

sin(\theta)=\frac{BC}{AC}

Find the length side AC applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=11^2+9^2

AC^2=202

AC=\sqrt{202}\ units

so

sin(\theta)=\frac{9}{\sqrt{202}}

simplify

sin(\theta)=\frac{9\sqrt{202}}{202}

Remember that      

The point (11,-9) lies in Quadrant IV

then      

The value of sin(∅) is negative

therefore

sin(\theta)=-\frac{9\sqrt{202}}{202}

5 0
3 years ago
If a quadrilateral has vertices a(-2,2) b(2,3) c (3,-4) d(-3,-2) find the slope of AB,BC,CD,DA
FrozenT [24]
Slope AB=0.25
BC=-7
CD=-1/3
DA=4
4 0
3 years ago
How hard must someone pull on the unkown line and inwhat direction to keep the knot from moving ​
dolphi86 [110]

Answer:

4.4N, 263.4°

Step-by-step explanation:

The sum of all forces must add to zero:

The forces in the x-plane:

∑F = 3N + (cos 120°)*5N + x = 0

x = -(3N + (cos 120°)*5N)

x = -0.5N

The forces in the y-plane:

∑F = (sin 120°)*5N + y = 0

y = -(sin 120°)*5N = -√(3/4)*5N = -4.3N

The magnitude of the unknown force U is:

U = √(x² + y²) = √19 = 4.4N

The direction is given by:

tanФ = y/x

Ф = 263.4°

4 0
3 years ago
!!!!!!!!!!!!!!!! x= and y=
kap26 [50]

Answer:

Y=16

X=32

Step-by-step explanation:

ï just know you need to do more meth

7 0
3 years ago
X|−10|=3<br><br>find all possible values of x
hram777 [196]

Answer:

x=13

Step-by-step explanation:

so,x-10=3

or,x=3+10

or,x=13

therefore, x=13

4 0
3 years ago
Read 2 more answers
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