PLEASE HELP ME PLEASE PLEASE PLEASE
1 answer:
You might be interested in
The graph of is given by,
Here given the function is
when , then it passes through the origin (0,0).
When
Since we know that, , then the function has maximum height at
.
Again when , again the function is 0.
So clearly the function is the Oscillating function.
Using graphing calculator we get the graph of function ,
Learn more about Trigonometric Function here -
#SPJ10
Equation of a circle is (x-x1)+(y-y1)=r²
when x1 and y1 are the coordinates of the centre
So you can substitute the centre in to get (x-5)²+(y+9)²=r²
When you draw a diagram it's obvious the radius is 9
9²=81
Therefore equation is (x-5)²+(y+9)²=81
Any questions, just ask :)
when x1 and y1 are the coordinates of the centre
So you can substitute the centre in to get (x-5)²+(y+9)²=r²
When you draw a diagram it's obvious the radius is 9
9²=81
Therefore equation is (x-5)²+(y+9)²=81
Any questions, just ask :)