Answer:
<h2>0.64</h2>
Step-by-step explanation:
4.48/7
7 into 4 (0 times)
Bring next number down 4.48 ⬇️
7 into 44 (6 times, 2 left over)
Bring next number down 4.48 ⬇️
7 into 28 (4 times)
Answer 0.64
I'm always happy to help :)
Answer:
680 games
Step-by-step explanation:
Suppose that 681 tennis players want to play an elimination tournament.
1st round:
One of 681 players, chosen at random, sits out that round and 680 players play. There will be 340 winners plus one player which sits - 341 players for the next round and 340 games
2nd round:
There will be 170 winners plus one player which sits - 171 players for the next round and 170 games
3rd round:
There will be 85 winners plus one player which sits - 86 players for the next round and 85 games
4th round:
There will be 43 winners - 43 players for the next round and 43 games
5th round:
There will be 21 winners plus one player which sits - 22 players for the next round and 21 games
6th round:
There will be 11 winners - 11 players for the next round and 11 games
7th round:
There will be 5 winners plus one player which sits - 6 players for the next round and 5 games
8th round:
There will be 3 winners - 3 players for the next round and 3 games
9th round:
There will be 1 winner plus one player which sits - 2 players for the next round and 1 game
10th round - final:
1 champion and 1 game.
In total,
340 + 170 + 85 + 43 + 21 + 11 + 5 + 3 + 1 + 1 = 680 games
What is the question now??
Answer:
The zeros are:
- The function has three distinct real zeros.
Hence, option (B) is true.
Step-by-step explanation:
Given the expression
Let us determine the zeros of the function by putting h(x) = 0 and solving the expression
switch sides
as
so
Using the zero factor principle
so
Thus, the zeros are:
It is clear that there are three zeros and all the zeros are distinct real numbers.
Therefore,
- The function has three distinct real zeros.
Hence, option (B) is true.
Si estas haciendo una linea recta vas a necesitar dos puntos. Los encuentras poniendo un numero por x en la formula para que te de un numero, y. Y te va dar (x, y). Lo haces otravez con otro valor de x y ese te va dar (x2, y2). Y luego los conectas con una linea.
