Question

Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot

Answer 1

Answer:

$\angle A \cong \angle D$

Step-by-step explanation:

The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.

Thus, since John already knows that $\overline{AB} \cong \overline{DE}$ and $\overline{AC} \cong \overline{DF}$, therefore, an additional information showing that the angle between $\overline{AB}$ and $\overline{DE}$ in ∆ABC is congruent to the angle between $\overline{AC}$ and $\overline{DF}$ in ∆DEF.

For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be $\angle A \cong \angle D$.

See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.