The possible value of the third length is an illustration of Triangle inequality theorem
The possible third lengths are 4 units and 6 units
<h3>How to determine the possible length of the third side?</h3>
To determine the third length, we make use of the following Triangle inequality theorem.
a + b > c
Let the third side be x.
So, we have:
x + 6 > 3
x + 3 > 6
3 + 6 > x
Solve the inequalities
x > -3
x > 3
x < 9
Remove the negative inequality value.
So, we have:
x > 3 or x < 9
Rewrite as:
3 < x or x < 9
Combine the inequality
3 < x < 9
This means that the possible value of the third length is between 3 and 9 (exclusive)
Hence, the possible third lengths are 4 units and 6 units
Read more about Triangle inequality theorem at:
brainly.com/question/2403556
Answer:
Domestic Stamps: 60
Foreign Stamps: 36
Step-by-step explanation:
96 - 24 = 72
72 ÷ 2 = 36
36 + 24 = 60
d - f = 24
60 - 36 = 24
24 = 24
d + f = 96
60 + 36 = 96
96 = 96
Standard error of the mean is computed by:
Standard error = SD/ sqrt N
Where:
N is the sample size
SD is the standard deviation
To get the standard deviation, you need to get the sqrt of
the variance = sqrt 9 = 3
So plugging in our data:
Standard error = 3 / sqrt (16)
= 0.75
For a better understanding of the solution provided here, please find the diagram attached.
In the diagram, ABCD is the room.
AC is the diagonal whose length is 18.79 inches.
The length of wall AB is 17 inches.
From the given information, we have to determine the length of the BC, which is depicted a
, because for the room to be a square, the length of the wall AB must be equal to the length of the wall BC.
In order to determine the length of the wall BC, or
, we will have to employ the Pythagoras' Theorem here. Thus:


Thus,
inches
and hence, the given room is not a square.
<u>Given</u>:
If you are dealt 4 cards from a shuffled deck of 52 cards.
We need to determine the probability of getting two queens and two kings.
<u>Probability of getting two queens and two kings:</u>
The number of ways of getting two queens is 
The number of ways of getting two kings is 
Total number of cases is 
The probability of getting two queens and two kings is given by

Substituting the values, we get;

Simplifying, we get;



Thus, the probability of getting two queens and two kings is 0.000133