Answer:
76
Step-by-step explanation:
(8)²+12=76
Step 1, because when distributing -5(x-1), both the negatives on the -5 and -1 cancel out. The correct outcome would be positive 5, but instead Luca puts -1.
Answer:
I would stay direct vartation
Step-by-step explanation:
For example, if y varies directly as x, and y = 6 when x = 2, the constant of variation is k = = 3. Thus, the equation describing this direct variation is y = 3x.
Answer:
Step-by-step explanation:
I don't know where you are in your class, or even what chapter you are in, but I solved this using a right triangle.
We don't need to know the angles, just the sides.
c is the hypotenuse, the line at a tilt
b is the adjacent line, directly below c
a is the opposite line
c = 13
a= 12
b = ?
In order to find b, we use the Pythagorean Theorem,
, but we need to rearrange the problem to where we are solving for b instead of c, ![b^{2} = a^{2} + c^{2}](https://tex.z-dn.net/?f=b%5E%7B2%7D%20%3D%20a%5E%7B2%7D%20%2B%20c%5E%7B2%7D)
![b^{2} = (12)^{2} + (13)^{2}\\b^{2} = 144 + 169\\b^{2} = 313 \\\sqrt{b^{2} } = \sqrt{313}\\ b = 17.69](https://tex.z-dn.net/?f=b%5E%7B2%7D%20%3D%20%2812%29%5E%7B2%7D%20%2B%20%2813%29%5E%7B2%7D%5C%5Cb%5E%7B2%7D%20%3D%20144%20%2B%20169%5C%5Cb%5E%7B2%7D%20%3D%20313%20%5C%5C%5Csqrt%7Bb%5E%7B2%7D%20%7D%20%3D%20%5Csqrt%7B313%7D%5C%5C%20b%20%3D%2017.69)
So, b = 17.69
Now, we need to evaluate each of the trig. functions:
![sin = \frac{opposite}{hypotenuse} = \frac{12}{13} \\csc = \frac{hypotenuse}{opposite} = \frac{13}{12} \\cos = \frac{adjacent}{hypotenuse} = \frac{17.69}{13} \\sec = \frac{hypotenuse}{adjacent} = \frac{13}{17.69}\\tan = \frac{opposite}{adjacent} = \frac{12}{17.69}\\cot = \frac{adjacent}{opposite} = \frac{17.69}{12}](https://tex.z-dn.net/?f=sin%20%3D%20%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D%20%3D%20%5Cfrac%7B12%7D%7B13%7D%20%5C%5Ccsc%20%3D%20%5Cfrac%7Bhypotenuse%7D%7Bopposite%7D%20%3D%20%5Cfrac%7B13%7D%7B12%7D%20%20%5C%5Ccos%20%3D%20%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D%20%3D%20%5Cfrac%7B17.69%7D%7B13%7D%20%20%5C%5Csec%20%3D%20%5Cfrac%7Bhypotenuse%7D%7Badjacent%7D%20%3D%20%5Cfrac%7B13%7D%7B17.69%7D%5C%5Ctan%20%3D%20%5Cfrac%7Bopposite%7D%7Badjacent%7D%20%3D%20%5Cfrac%7B12%7D%7B17.69%7D%5C%5Ccot%20%3D%20%5Cfrac%7Badjacent%7D%7Bopposite%7D%20%3D%20%5Cfrac%7B17.69%7D%7B12%7D)
So, there is your answers, hope that is what you are looking for.
Budget of a film = $1300
Percentage of budget that was spent on costume = 43%
Money spent on costumes :
![= \tt43\% \: \: of \: \: 1300](https://tex.z-dn.net/?f=%20%3D%20%5Ctt43%5C%25%20%5C%3A%20%5C%3A%20%20of%20%5C%3A%20%20%5C%3A%201300)
![= \tt \frac{43}{100} \times 1300](https://tex.z-dn.net/?f=%20%3D%20%5Ctt%20%5Cfrac%7B43%7D%7B100%7D%20%20%5Ctimes%201300)
![= \tt \frac{43 \times 1300}{100}](https://tex.z-dn.net/?f=%20%3D%20%5Ctt%20%5Cfrac%7B43%20%5Ctimes%201300%7D%7B100%7D%20)
![=\tt \frac{55900}{100}](https://tex.z-dn.net/?f=%20%3D%5Ctt%20%20%5Cfrac%7B55900%7D%7B100%7D%20)
![\color{plum}=\tt\$ 559](https://tex.z-dn.net/?f=%20%5Ccolor%7Bplum%7D%3D%5Ctt%5C%24%20559)
▪︎<em>Therefore, the money they spent on costumes = $599</em>