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2 years ago

I need help RATS :) EHEHEHEHEHEHEEHEHEHEHEHEHEHEHEHEHEEHEHHEHEEHEHEH

Mathematics

2 answers:

galina1969 [7]2 years ago

4 0

Answer:

Ok, so the answer is 3.5

Step-by-step explanation:

From what I could see it says walked for 14 around her block 4 times so your answer is 3.5 because if (Let's call her Patricia) Patricia walked around her block 4 times in 14 minutes, we have to find the unit rate, therefore we have to divide 14 by 4 as shown below

$14/4=3.5$

Thus your only viable solution is 3.5

Hope this Helps! Also, I would appreciate it if I could be rewarded with Brainliest, I work hard on these answers and I would enjoy it, you see my goal is to reach Genius status, as to provide many more helpful answers and help many more people. Even so, I hope that I have come of assistance to you!

Vesnalui [34]2 years ago

3 0

Answer:

- Can't see the question tbfr

Step-by-step explanation:

but here's an explanation for understandment - 14 divided by 4 is 3.5 so that would be the unit rate

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One True Love? A survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each pe

sertanlavr [38]

Answer:

99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of people who disagree with the statement = $\frac{1812}{2625}$ = 0.69

n = sample of respondents = 2625

p = population proportion of people who disagree with statement

Here for constructing 99% confidence interval we have used One-sample z proportion statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.58 & 2.58}

P(-2.58 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.58) = 0.99

P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.69-2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ , $0.69+2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ ]