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Illusion [34]
3 years ago
12

Find it ASAP What is the whole 85% of 17

Mathematics
1 answer:
Paraphin [41]3 years ago
4 0
If you're just trying to find 85% of 17, you would do 17 * .85 which gives us 14.45
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HELP QUICK PLEASE!!!!
just olya [345]

Answer:

five

Step-by-step explanation:

when putting the image into a net you can count 5 sides

3 0
3 years ago
Read 2 more answers
3x to the power of 3 + 21x squared + 36x = 0 by factoring the quadratic equation.
Diano4ka-milaya [45]

Answer:

x = 0, -4 and -3.

Step-by-step explanation:

The given expression is "3x to the power of 3 + 21x squared + 36x = 0".

We can write this expression as follows :

3x^3+21x^2+36x=0

Taking 3x common.

3x(x^2+7x+12)=0\\\\3x=0\ \text{and}\ (x^2+7x+12)=0

x = 3

x^2+7x+12=0\\\\x^2+3x+4x+12=0\\\\x(x+3)+4(x+3)=0\\\\(x+4)(x+3)=0\\\\x=-4,-3

Hence, the solution of the given quadratic equation are x = 0, -4 and -3.

5 0
3 years ago
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Alinara [238K]
It is the first answer, loss of $701.80
5 0
3 years ago
Can someone please help mee
devlian [24]

Answer:

B is (7,-4) C is (7,-2) D is (5,0)

Step-by-step explanation:

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5 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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