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Diano4ka-milaya [45]
3 years ago
7

Evaluate 5x for each value of x x = 0.3

Mathematics
1 answer:
Musya8 [376]3 years ago
4 0

Answer:

0.1

Step-by-step explanation:

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A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random
Yuliya22 [10]

Answer:

b) independent samples t-test

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Our notation on this case :  

n_1 =5 represent the sample size for group 1  

n_2 =5 represent the sample size for group 2  

We can calculate the mean and deviation for eaach group with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =5.92 represent the sample mean for the group 1  

\bar X_2 =5.74 represent the sample mean for the group 2  

s_1=1.88 represent the sample standard deviation for group 1  

s_2=1.81 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}  

And now we can calculate the statistic:  

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

The degrees of freedom are given by:  

df=5+5-2=8

And now we can calculate the p value using the altenative hypothesis:  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

7 0
3 years ago
The slope of a line passing through the points (-2, 3) and (2, 7) is 1. a)True b) False
Paraphin [41]
<h3>Answer: True</h3>

Slope formula

m = (y2 - y1)/(x2 - x1)

m = (7 - 3)/(2 - (-2))

m = (7 - 3)/(2 + 2)

m = 4/4

m = 1

7 0
2 years ago
Read 2 more answers
Find the value of c and AB if B is between A and C,AB=2r,AC=-5and BC=7​
elena-14-01-66 [18.8K]

AB=2r

BC=7

AC=AB+BC

-5=2r+7

-12=2r

-6=r

AB=-12

6 0
3 years ago
Use the distributive property to simplify 1/6 × (36+1/2)
kicyunya [14]
1/6(36 + 1/2) = 6 + 1/12 = 72/12 + 1/12 = 73/12
5 0
2 years ago
Express in the simplest form 777:147​
Dvinal [7]

Answer:

your answer should be 37:7

Try to reduce the ratio further with the greatest common factor (GCF).

The GCF of 777 and 147 is 21

Divide both terms by the GCF, 21:

777 ÷ 21 = 37

147 ÷ 21 = 7

The ratio 777 : 147 can be reduced to lowest terms by dividing both terms by the GCF = 21 :

777 : 147 = 37 : 7

Therefore:

777 : 147 = 37 : 7

3 0
3 years ago
Read 2 more answers
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