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3 years ago

The base unit used to measure weight in metric system is

Mathematics

2 answers:

Hitman42 [59]3 years ago

8 0

Grams and kilograms

erastova [34]3 years ago

7 0

For this case we have, by definition:

In the metric system, the basic unit for length is the meter, (m)

The base unit for mass is the Kilogram., (Kg)

The base units for gravity are $\frac {m} {s ^ 2}$

The weight is the measure of the force of gravity of an object.

So, what Weight = Mass * gravity

Then the base units to measure the weight are:

$Kg * \frac {m} {s ^ 2} = Newton = N$

Answer:

The Newton

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Leni [432]

Answer: $\dfrac{2x^2-1}{x(x^2-1)}$

Step-by-step explanation:

The given function : $y=\ln(x(x^2 - 1)^{\frac{1}{2}})$

$\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}$ [ $\because \ln(ab)=\ln a +\ln b$ ]

$\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}$ [ $\because \ln(a)^n=n\ln a$ ]

Now , Differentiate both sides with respect to x , we will get

$\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1)$ (By Chain rule)

[Note : $\dfrac{d}{dx}(\ln x)=\dfrac{1}{x}$ ]

$\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)$

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$=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}$

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3 years ago

Read 2 more answers

There are two numbers which sum to 23. If one number is seven less than four times the other, find the numbers.

mart [117]

Answer:

Numbers are 6 and 17.

Step-by-step explanation:

Let the two numbers are 'a' and 'b'.

"Sum of these numbers = 23"

a + b = 23 --------(1)

"One number is 7 less than 4 times the other"

a = 4b - 7 ---------(2)

Substitute the value of 'a' in equation (1) from equation (2)

(4b - 7) + b = 23

5b - 7 = 23

5b = 23 + 7

5b = 30

b = 6

From equation (2),

a = 4b - 7

a = 4×6 - 7

a = 24 - 7

a = 17

Therefore, the numbers are 6 and 17.

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3 years ago