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Rudik [331]
3 years ago
9

The base unit used to measure weight in metric system is

Mathematics
2 answers:
Hitman42 [59]3 years ago
8 0
Grams and kilograms
erastova [34]3 years ago
7 0

For this case we have, by definition:

In the metric system, the basic unit for length is the meter, (m)

The base unit for mass is the Kilogram., (Kg)

The base units for gravity are\frac {m} {s ^ 2}

The weight is the measure of the force of gravity of an object.

So, what Weight = Mass * gravity

Then the base units to measure the weight are:

Kg * \frac {m} {s ^ 2} =  Newton = N

Answer:

The Newton

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Find the equation of a circle whose endpoints of the diameter are (15, - 3) and (7,3). The equation of the circle is (Simplify y
Nana76 [90]

Answer:

(x - 11)² + y² = 25

Step-by-step explanation:

First find the center

O = ( (15 +7 / 2), (-3 + 3)/2 )

O = (11, 0)

Then find the radius squared

use the distance formula from the center to either end point of the diameter

r² = (15 - 11)² + (-3 - 0)²

r² = 16 + 9

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Formula for circle

(x - h)² + (y - k)² = r²

(h, k) is the center = (11, 0)

The equation is

(x - 11)² + y² = 25

8 0
3 years ago
All the numbers that round to 940,000 when rounded to the nearest ten thousand?
timurjin [86]

The required number is 940,000.

It is required to find the solution.

<h3>What is rounded number?</h3>

A number that is easily multiplied, divided, etc., and especially a number that ends in zero.

Solution:

To round a number to the nearest 10,000, check the thousands digit to decide whether to round up or round down. If the thousands are 5000 or more, round up. If they are 4999 or less, round down. 45,000 to the nearest 10,000 is 50,000.

The numbers that round to 940,000 when rounded to the nearest ten thousand is  940,000.

Therefore, the required number is 940,000.

Learn more about rounded number here:

brainly.com/question/15265892

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2 years ago
What is the interquartile range of the data set?
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3 years ago
Miguel buys 100 feet of fence to enclose a rectangular area of his backyard so his dog can run freely. What is the maximum area,
sdas [7]
Suppose the length of the triangle is x, if the perimeter of the rectangle is 100 ft, the width of the rectangle will be (50-x) ft.
Area of rectangle will be:
A=length*width
A=x(50-x)
A=50x-x^2
at maximum area, dA/dx=0
thus
dA/dx=50-2x=0
solving for x we get
2x=50
x=25
thus for maximum area length=25 ft
the size of the width will be
50-x=50-25=25 ft
thus the maximum area will be:
25*25=625 sq. feet
5 0
3 years ago
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