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3 years ago

The base unit used to measure weight in metric system is

Mathematics

2 answers:

Hitman42 [59]3 years ago

8 0

Grams and kilograms

erastova [34]3 years ago

7 0

For this case we have, by definition:

In the metric system, the basic unit for length is the meter, (m)

The base unit for mass is the Kilogram., (Kg)

The base units for gravity are $\frac {m} {s ^ 2}$

The weight is the measure of the force of gravity of an object.

So, what Weight = Mass * gravity

Then the base units to measure the weight are:

$Kg * \frac {m} {s ^ 2} = Newton = N$

Answer:

The Newton

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Each year, more than 2 million people in the United States become infected with bacteria that are resistant to antibiotics. In p

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Null hypothesis:H₀:- There is no significant difference between in drug resistance between the two states

Alternative Hypothesis :H₁:

There is significant difference between in drug resistance between the two states

B)

The calculated value Z = 2.7261 > 2.054 at 0.02 level of significance

Rejected H₀

There is a significant difference in drug resistance between the two states.

P - value = 0.0066

P - value = 0.0066 < 0.02

D)

1) Reject H₀

There is a significant difference in drug resistance between the two states.

Step-by-step explanation:

Step(i):-

Given first sample size n₁ = 174

Suppose that, of 174 cases tested in a certain state, 11 were found to be drug-resistant.

First sample proportion

$p_{1} = \frac{x_{1} }{n_{1} } = \frac{11}{174} = 0.0632$

Given second sample size n₂ = 375

Given data Suppose also that, of 375 cases tested in another state, 7 were found to be drug-resistant

Second sample proportion

$p_{2} = \frac{x_{2} }{n_{2} } = \frac{7}{375} = 0.0186$

Step(ii):-

Null hypothesis:H₀:- There is no significant difference between in drug resistance between the two states

Alternative Hypothesis :H₁:

There is significant difference between in drug resistance between the two states

Test statistic

$Z = \frac{p_{1}-p_{2} }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }$

Where

$P = \frac{n_{1}p_{1} +n_{2} p_{2} }{n_{1} +n_{2} }$

$P = \frac{174 (0.0632) + 375 (0.0186) }{174+375 } = \frac{17.9718}{549} = 0.0327$

Q = 1 - P = 1 - 0.0327 = 0.9673

Step(iii):-

Test statistic

$Z = \frac{p_{1}-p_{2} }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }$

$Z = \frac{0.0632-0.0186 }{\sqrt{0.0327 X 0.9673(\frac{1}{174 }+\frac{1}{375 } ) } }$

Z = 2.7261

Level of significance = 0.02 or 0.98

The z-value = 2.054

The calculated value Z = 2.7261 > 2.054 at 0.02 level of significance

Reject H₀

There is a significant difference in drug resistance between the two states.

P- value

P( Z > 2.7261) = 1 - P( Z < 2.726)

= 1 - ( 0.5 + A (2.72))

= 0.5 - 0.4967

= 0.0033

we will use two tailed test

2 P( Z > 2.7261) = 2 × 0.0033

= 0.0066

P - value = 0.0066 < 0.02

Reject H₀

There is a significant difference in drug resistance between the two states.

8 0

3 years ago