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lara [203]
2 years ago
5

Point LL is located at (4,5)(4,5) on the coordinate plane. Point LL is reflected over the yy-axis to create point L'L ′ . What o

rdered pair describes the location of L'?L ′ ?
Mathematics
1 answer:
Virty [35]2 years ago
8 0

Answer:

(-4, 5)

Step-by-step explanation:

Since the pint is reflected over the y-axis, its y-coordinate remains the same.

Point (4, 5) has 4 as its x-coordinate. That is 4 units right of the y-axis. The reflection has -4 as its x-coordinate which is 4 units left of the y-axis.

Answer: (-4, 5)

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Nonamiya [84]

Answer:

1/6

Step-by-step explanation:

the form you're using is slope-intercept. That is

y=mx+b

where y= y coordinate

m=slope

x= x coordinate

and b= y intercept

so, m in that equation is 1/6, so the slope is 1/6

Hope this helps!

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The enthalpy of a reaction can be measured using a _____.
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The enthalpy of a reaction can be measured using a Calorimeter
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Tell what you would do to isolate the variable.
Mariana [72]
<span>Simplifying x + -1.4 = 7.82 Reorder the terms: -1.4 + x = 7.82 Solving -1.4 + x = 7.82 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '1.4' to each side of the equation. -1.4 + 1.4 + x = 7.82 + 1.4 Combine like terms: -1.4 + 1.4 = 0.0 0.0 + x = 7.82 + 1.4 x = 7.82 + 1.4 Combine like terms: 7.82 + 1.4 = 9.22 x = 9.22 Simplifying x = 9.22</span>
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3 years ago
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What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

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The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
3 years ago
Different hotels in a certain area are randomly selected, and their ratings and prices were obtained online. Using technology, w
mash [69]

Answer:

Option C) The symbol y represents the predicted value of price.

Step-by-step explanation:

We are given the following in the question:

We find a regression equation with x representing the ratings and y representing price.

The equation has a slope of 130 and a y-intercept of 350.

Comparing with the slope intercept form:

y = mx + c\\\text{where m is the slope and c is the y intercept}

Thus, we can write the equation as:

y = 130x + 350

Here, y is the predicted variable that is the price, c is the price of hotel when a rating of 0 is given.

Thus, symbol y represents:

C) The symbol y represents the predicted value of price.

5 0
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