Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
Answer:
1800 mi
Step-by-step explanation:
Recall that (distance) = (rate)(time).
Here, (distance) = (200 mi/hr)(8.5 hr) = 1800 mi
So a general harmonic equation is Asin(2πt/T). Little t is just a variable. 6 inches is the height of one maximum and one minimum from equilibrium, so that is the amplitude A. T is the period, or the time of one cycle (or wavelength), which is 2 seconds.
The equation is therefore (in terms of seconds and inches), 6*sin(2πt/2), or 6*sin(πt).
Answer:
If 5x+12=44 then value of 5x-12 is 20
Step-by-step explanation:
5x + 12 = 44
- The first step, we have to find the value of x
5x + 12 = 44
5x = 44 - 12
5x = 32
x = 32/5
x = 6.4
- After that, insert the value of x into 5x - 12
5x - 12 = ...
5 ( 32/5 ) - 12
= 32 - 12
= 20
251,000
For this check the hundreds, tens, ones. If it's 500 of more round it up
