9/27, 12/27, 16/27
So this is a geometric sequence as each term is 4/3 the previous term.
Since the common ration is greater than one the sum of the series diverges, it does not exist. (The sum just keeps getting larger and larger)
For a geometric series to have a sum r^2<1
So that the normal sum....
s(n)=a(1-r^n)/(1-r) becomes if r^2<1
s=a/(1-r)
Answer: p=11.2
Step-by-step explanation:
14.3p- 32.24 =127.92
14.3p - 32.24 + 32.24 = 127.92 + 32.24
14.3p = 160.16
p = 160.16 ÷ 14.3
p = 11.2
Hope this can help you :)
ever heard of gogle Answer:
coool bro but i dont rememeber asking
Explanation:
If you want to put a number as a fraction, just put it over 100.
Eg 82.5 as a fraction is:
82.5
-------
100