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matrenka [14]
3 years ago
10

If 8 identical blackboards are to be divided among 4 schools, how many divisions are possible? how many if each school must rece

ive at least 1 blackboard?
Mathematics
1 answer:
DaniilM [7]3 years ago
8 0
Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then 

( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165

For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35
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Answer:

C.

Step-by-step explanation:

For an angle to be supplementary to another angle, they must be equal to 180. Angles 6, 10, 13, and 9 are all supplementary to angle 16. Although there are more choices in different answers it wouldn't work with question, so C is the right answer.

Angle 16 is supplementary to angle 9 by the Same Side Interior Angles Theorem, which makes it supplementary to angle 10 by the Alternate Exterior Angles Theorem, which is also congruent to angle 13 by the Vertical Angles Theorem, which is also supplementary to angle 6 by the Alternate Exterior Angles Theorem.

8 0
3 years ago
Which of the following statements would be correct to use when proving that limx→4(3x−4)=8?
Fudgin [204]

Answer:

Option c

Step-by-step explanation:

given that limit x tending to 4 of the function (3x-4) is 8

This implies for all values of x such that for epsilon >0 arbitrary small ,

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this is equivalent to the option c.

Proof:

Consider

||x-4||

Hence it follows that option C is right.

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