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lions [1.4K]
2 years ago
9

1. If 335g water at gains 1,666.11 J of heat, how much does the temperature of the

Chemistry
1 answer:
Setler79 [48]2 years ago
4 0

Answer:

Explanation:

cold and hot are temperatures

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Alpine Marmots are a type of rodent that have the ability to decrease their body activity to conserve food. These marmots most l
tia_tia [17]

Hello!

The answer is C. Hibernate during the cold winter months.

Why?

Alpine marmots are known for having a long hibernation duration which starts in October (winther) and ends in April (summer) (about 7 months). During this long period, they are able to reduce their bear beats from 200 per minute to just 30 or 38 beats, and their breaths from 60 breaths/minute to 1-3 breaths/minute, guaranteeing an extreme energy saving process.

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5 0
3 years ago
( copper is Cu) How many Copper atoms in 3CuSO 4<br><br> Need help ASAP !!!!!
nydimaria [60]
There are the 3 copper atoms in 3CuSO4. I hope this helps!!
5 0
3 years ago
The blue color of the sky results from the scattering of sunlight by air molecules. The blue light has a frequency of about 7.5
vazorg [7]

A) c = 3 x 10^8 m/s 
f = 7.15 x 10^14 Hz 
c = λ x f (=) λ = 3 x 10^8 / 7.15 x 10^14 = 4.19 x 10^-7 m = 419.6 nm 

B) E = h  f 
H = Planck's constant = 6.63 x 10^-34 J/s 
E = 6.63 x 10^-34 x 7.15 x 10^14 = 4.74 x 10^-19 J

Read more on Brainly.com - brainly.com/question/5760368#readmore
3 0
4 years ago
What is the concentration of the murexide soution with a transmittance of 28.65%. (molar absorptivity = 3847)
Ainat [17]

Answer:

The concentration of the murexide solution is 0.0000745 M

Explanation:

From Beer-Lambert's law,

A = εlc

A = Absorbance = 28.65% = 0.2865

ε = molar absorptivity = 3847 M/cm

l = path length = 1cm

c = concentration in mol/L = ?

c = A/εl = 0.2865/(3847×1) = 0.0000745 mol/L

Hope this Helps!

6 0
3 years ago
What is the molality of a solution made by dissolving 137.9g of sucrose in 414.1g of water?
Daniel [21]

Answer: 2.71 moles of solute for every 1 kg of solvent.

Explanation: As you know, the molality of a solution tells you the number of moles of solute present for every 1 kg of the solvent.This means that the first thing that you need to do here is to figure out how many grams of water are present in your sample. To do that, use the density of water.500.mL⋅1.00 g1mL=500. g Next, use the molar mass of the solute to determine how many moles are present in the sample.115g⋅1 mole NanO385.0g=1.353 moles NaNO3So, you know that this solution will contain 1.353moles of sodium nitrate, the solute, for 500. g of water, the solvent.In order to find the molality of the solution, you must figure out how many moles of solute would be present for 1 kg=103g of water.103g water⋅1.353 moles NaNO3500.g water=2.706 moles NaNO3You can thus say that the molality of the solution is equal to molality=2.706 mol kg−1≈2.71 mol kg−1 The answer is rounded to three sig figs.

8 0
3 years ago
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