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Julli [10]
4 years ago
7

Pablo drove 260 miles using 12 gallons of gas. at this rate, how many gallons of gas would he need to drive 286 miles?

Chemistry
1 answer:
Naddik [55]4 years ago
7 0
260 miles with 12 gallons of gas
260 miles/12 gallons=21.6667 miles/1 gallon
286 miles/(21.6667 miles/1 gallon)=13.2 gallons of gas
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What does variable mean in a science project.
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Well, an independent variable ids the thing that  stays the same and a dependent variable is the thing that changes.

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Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2N
Lera25 [3.4K]

Answer:

NH3

Explanation:

2NH3(aq)+CO2(aq)→CH4N2O(aq)+H2O(l)

So for two moles of NH3 we need one mole of CO2. So let's count moles for each reagent.

n(NH3)=m(NH3)/M(NH3)=135700/17,03=7968.29 mol

n(CO2)=m(CO2)/M(CO2)=211400/44.01=4803.45 mol

From equation we have to divide n(NH3) by 2 because we need two equivalent per one CO2. That will be 3984.145. So the limiting agent is NH3 because it's not enough of it to react with all CO2

4 0
3 years ago
- Which of the following is an example of physical change?
dalvyx [7]
B as the glass just changes form as it shattered but the chemical composition is same as it was before
5 0
3 years ago
draw two lewis structures for a compound with the formula c2h6o and compare the boiling points of the two molecules
Volgvan

Answer:

See explanation and images attached

Explanation:

There are two compounds that could have molecular formula of C2H6O, they are ethanol and methoxy methane (trivial name: methyl ether).  The structures of the two compounds are shown in the image attached as obtained from quora.

The boiling point of methoxymethane is -24.8°C  while that of ethanol is about 78.5°C. The reason for the high boiling point of ethanol is the presence of intermolecular hydrogen bonding leading to a stronger intermolecular interaction compared to methoxymethane molecules held together only by very weak dispersion forces.

4 0
3 years ago
If a 45.6 g piece of aluminum has a density of 2.1 g/mL, what volume would it have?
Mashcka [7]

Answer:

\boxed {\tt 21.7142857 \ mL}

Explanation:

The density formula is:

d=\frac{m}{v}

Rearrange this formula for v, volume. Multiply by v, then divide by d.

d*v=\frac{m}{v}

d*v=m

\frac{d*v}{d} =\frac{m}{d}

v=\frac{m}{d}

Volume can be found by dividing the mass by the density. The mass of the aluminum is 45.6 grams and the density is 2.1 grams per milliliter.

v=\frac{45.6 \ g }{ 2.1 \ g/mL}

Divide. Note the grams, or g, will cancel out.

v=\frac{45.6 }{2.1 \ g}

v= 21.7142857 \ mL

The volume of the aluminum is 21.7142857 milliliters.

3 0
4 years ago
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