Question

6(x-3)+10=2(4x-5) pls help

Answer 1

Answer:

$x=1$

Step-by-step explanation:

$6\left(x-3\right)+10=2\left(4x-5\right)$

We'll use the distributive property to multiply 6 by (x-3):

$6x-8 +10=2(4x-5)$

*Distributive property*, multiply 2 by (4x-4)

$6x-8=8x-10$

Add 8 from both sides:

$6x-8+8=8x-10+8$

$6x=8x-2$

Subtract 8x from both sides:

$6x-8x=8x-2-8x$

$-2x=-2$

Divide both sides by -2:

$\cfrac{-2x}{-2}=\cfrac{-2}{-2}$

$x=1$

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Answer 2

X=1
6x-18+10=8x-10
6x-8x=-10-10+18
-2x=-2
x=-2/-2=1



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