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andrew-mc [135]
3 years ago
8

Question #2, Help...?

Mathematics
2 answers:
meriva3 years ago
6 0

Answer:

9(8w+9x-10)

72w+10x-90

Step-by-step explanation:

All you have to do is multiply 9 by everything inside the parentheses.

Hope it helps! :)

Dominik [7]3 years ago
4 0

Hello There!

Here's a explanation!

9(8w+9x-10)

Apply the distributive law:

9(8w+9x-10)=9 · 9x+9(-10)

=9 · 8w+9 ·  9x+9(-10)

Simplify:

9 · 8w+9 · 9x+9(-10)

ANSWER!

= 72w+81x-90

Hopefully,, this helps you!!

AnimeVines

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Harlamova29_29 [7]

Answer:

Step-by-step explanation:

1.  (a) 24 X 3/4= 18 multiplication

you have to multiply to get a smaller answer since you are using a fraction.

2. (a) 24 / (-3/4)= -32 division

you have to divide to get a bigger number than started since you are using a fraction

3. (A) 12-15= -3 subtraction

when you subtract a bigger number than the first number you end up normally with a negative number

4. (a) 12 -(-15) subtraction

when you subtract with a negative number you distribute so the two negatives cancel out and it become an addition sign. (if you look at it the two negatives and the parenthesis looks like an addition sign (+)

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when you divide two negative values you will always get a positive answer. And again dividing a fraction will get you a bigger answer.

8 0
3 years ago
Find the minimum cost of producing 60000 units of a product, where x is the number of units of labor, at $99 per unit, and y is
Y_Kistochka [10]

Answer:

The minimum cost of producing 60000 units of a product is $105867

Step-by-step explanation:

Since x is the number of units of labor, at $99 per unit, and y is the number of units of capital expended, at $84 per unit, The cost C(x,y) is given by:

C(x, y) = 99x + 84y

P(x, y) = 100x^{0.25}y^{0.75}

For the minimum cost:

100x^{0.25}y^{0.75}=60000\\x^{0.25}(\frac{33x}{28} )^{0.75}=600\\x^{0.25}(\frac{33}{28} )^{0.75}x^{0.75}=600\\x^{0.25+0.75}*1.131=600

Using the langrage multiplier,

99=0.25(100)x^{-0.75}y^{0.75}\lambda...(1\\84=0.25(100)x^{0.25}y^{-0.25}\lambda...(2

Dividing both equation 1 and 2

y=\frac{33}{28}x

Substituting y=\frac{33}{28}x in 100x^{0.25}y^{0.75}=60000, we get:

x_{min}=530.44 labor units

Substituting x_{min}=530.44  labor units in y=\frac{33}{28}x, we get

y_{min}=\frac{33}{28}*530.44=625.16 labor unit

C(x, y) = 99x + 84y=99(530.44)+84(635.16) = $105867\\

The minimum cost of producing 60000 units of a product is $105867

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