Firstly, we will draw figure
now, we will draw a altitude from B to DC that divides trapezium into rectangle and right triangle
because of opposite sides of rectangle ABMD are congruent
so,
DM=AB=9
CM=CD-DM
CM=18-9
CM=9
now, we can find BM by using Pythagoras theorem
now, we can plug values
we get
now, we can find area of trapezium
now, we can plug values
and we get
so, area of of the trapezoid is 
..........Answer
Answer:
Step-by-step explanation:
rearrange the equation to the letter on the left side until you find an equation equal to one of the answers
Answer:
940.8 N
1254.4 N
Step-by-step explanation:
I would think the questions would be to calculate the forces at the top of the cube and at the sides. Thus:
On the top:
F = pressure * area
P = density * gravity * height
the height would be:
1m - 0.4m = 0.6m
replacing:
P = 1000 * 9.8 * 0.6 = 5880
A = (0.4) ^ 2 = 0.16
F = 5880 * 0.16
F = 940.8 N
On the sides:
dF = d * g * h * dA
dA = 0.4 * dh replacing
dF = 1000 * 9.8 * h * 0.4 * dh
dF = 3920 * h * dh
We integrate both sides and we have:
F = 3920 * (h ^ 2/2), h = 0.6 up to h = 1
F = (3920/2) * (1 ^ 2 - 0.6 ^ 2)
F = 1254.4 N
5≤x≤9 it can also be reversed as 9≥x≥5 which is the same thing
