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Y_Kistochka [10]
3 years ago
5

Passes through (-4,6) and (2,7)

Mathematics
2 answers:
ch4aika [34]3 years ago
8 0

Answer:

13/6

Step-by-step explanation:

mixas84 [53]3 years ago
4 0

Answer: 1/6

Step-by-step explanation:

There is a slope formula for this.

(x1,y1)= (-4,6)

(x2,y2)= (2,7)

Plug it into the formula:

\frac{7-6}{2-(-4)}= \frac{1}{6}

The slope is 1/6. It doesn't matter which set of coordinates you use for x1, y1.

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Can someone help me with this? thanks
Sergio039 [100]

Answer:

least to greatest:

-11.7   -11.4   20/40  11.6

6 0
3 years ago
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ANWER PLEASE FIRST TO ANSWER GETS BRAINLEST ANSWER
mamaluj [8]
I believe the answer is C 1,300

4 0
4 years ago
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A rectangular field has the area equal to that of a square field of side 60m.if the breadth of the rectangular field is 32m, fin
V125BC [204]

<u>Given</u> -

  • Area of rectangular field = Area of square field
  • side of square = 60m
  • breadth of the rectangular field = 32m

<u>To find</u> -

  • length of the rectangular field

<u>Solution</u> -

Area of square = side × side = (60 × 60)m² =

Area of square =3600m²

Hence,

Area of rectangular field = Area of square field = 3600m²

Area of rectangular field = l × b = 3600m²

=> l × 32m = 3600m²

=> l = \sf{\frac{3600}{32}\:m}

=> l = 112.5m

so, the length = 112.5m

5 0
3 years ago
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s344n2d4d5 [400]
10.5 ounce package- $3.51
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3 0
4 years ago
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I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

  • mROP = 125°
  • ∠ROP is a central angle

Then:

  • measure of arc RP, mRP = mROP = 125°

Given that

  • ∠QOS and ∠ROP are vertical angles

Then:

  • mQOS = mROP = 125°
  • measure of arc QS, mQS = mROP = 125°

Given that

  • ∠QOR and ∠SOP are vertical angles

Then:

  • mQOR = mSOP

Given that

  • The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

  • measure of arc QR, mQR = mQOR = 55°
  • measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0
3 years ago
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