Hm. This is an interesting problem.
Let's see if we can express each of these numbers in terms of x and make an algebra equation to help us solve.
Consecutive even numbers increase by 2.
Let's allow x to equal our first number.
Let's allow x + 2 to equal our 2nd number.
Let's allow x + 4 to equal our 3rd number.
When we add those together, their sum need to equal 50 more than the largest integer (our x + 4)
Let's set it up!
x + (x +2) + (x + 4) = (x + 4) + 50
Simplify!
3x + 6 = x + 54
Let's reorganize the left and right sides.
3x - x = 54 - 6
2x = 48
x = 24 (our 1st even number)
Now, let's check our answer!
24 + 26 + 28 = 78
78 - 50 = 28 Our highest integer.
The sum of consecutive integers 24, 26, 28 is 50 more than the highest integer.
The answer is the second one.
hope this helps !
Answer:
x = 15
Step-by-step explanation:
3x-7=x+23
Subtract x from each side
3x-x-7=x-x+23
2x -7 = 23
Add 7 to each side
2x-7+7 = 23+7
2x = 30
Divide by 2
2x/2 = 30/2
x = 15
B. $400 would be the answer when using front end estimation.
Answer:
8% of 1000 is 80
Step-by-step explanation:
