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ollegr [7]
3 years ago
14

An investment services company experienced dramatic growth in the last two decades. The following models for the company's reven

ue R and expenses or costs C (both in millions of dollars) are functions of the years past 1990. R(t) = 21.4e0.131t and C(t) = 18.6e0.131t (a) Use the models to predict the company's profit in 2020. (Round your answer to one decimal place.)(b) How long before the profit found in part (a) is predicted to double? (Round your answer to the nearest whole number.) years after 1990
Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Answer: a) 138.32 and b) 35 years approx.

Step-by-step explanation:

Since we have given that

R(t)=21.4e^{0.13t}\\\\C(t)=18.6e^{0.13t}

So, Profit is given by

Profit=R(t)-C(t)\\\\Profit=21.4e^{0.13t}-18.6e^{0.13t}\\\\Profit=e^{0.13t}(21.4-18.6)\\\\Profit=2.8e^{0.13t}

Difference in years of 1990 and 2020=30

So, Profit becomes :

P(30)=2.8e^{0.13\times 30}\\\\P(30)=2.8\times 49.40\\\\P(30)=138.32

(b) How long before the profit found in part (a) is predicted to double? (Round your answer to the nearest whole number.) years after 1990.

So, profit doubles , we get :

138.32\times 2=2.8e^{0.13t}\\\\276.65=2.8e^{0.13t}\\\\\dfrac{276.65}{2.8}=e^{0.13t}\\\\98.80=e^[0.13t}\\\\\ln 98.80=0.13t\\\\4.593=0.13t\\\\\dfrac{4..593}{0.13}=t\\\\35.33=t

Hence, a) 138.32 and b) 35 years approx.

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Round 342.79513 to the three significant figures
Pavel [41]

Answer:

343

Step-by-step explanation:

Because the 5 rounds 9 to a 10, making the 7 an 8, hence:

342.8

round the 2 to a 3 because the 8 round it up, making it 343

6 0
2 years ago
Jensen Tire & Auto is in the process of deciding whether to purchase a maintenance contract for its new computer wheel align
sasho [114]

Answer:

Step-by-step explanation:

Hello!

The given data corresponds to the variables

Y:  Annual Maintenance  Expense ($100s)

X: Weekly Usage  (hours)

n= 10

∑X= 253; ∑X²= 7347; \frac{}{X}= ∑X/n= 253/10= 25.3 Hours

∑Y= 346.50; ∑Y²= 13010.75; \frac{}{Y}= ∑Y/n= 346.50/10= 34.65 $100s

∑XY= 9668.5

a)

To estimate the slope and y-intercept you have to apply the following formulas:

b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} } = \frac{9668.5-\frac{253*346.5}{10} }{7347-\frac{(253)^2}{10} }= 0.95

a= \frac{}{Y} -b\frac{}{X} = 34.65-0.95*25.3= 10.53

^Y= a + bX

^Y= 10.53 + 0.95X

b)

H₀: β = 0

H₁: β ≠ 0

α:0.05

F= \frac{MS_{Reg}}{MS_{Error}} ~~F_{Df_{Reg}; Df_{Error}}

F= 47.62

p-value: 0.0001

To decide using the p-value you have to compare it against the level of significance:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The decision is to reject the null hypothesis.

At a 5% significance level you can conclude that the average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

b= 0.95 $100s/hours is the variation of the estimated average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

a= 10.53 $ 100s is the value of the average annual maintenance expense of the computer wheel alignment and balancing machine when the weekly usage is zero.

c)

The value that determines the % of the variability of the dependent variable that is explained by the response variable is the coefficient of determination. You can calculate it manually using the formula:

R^2 = \frac{b^2[sumX^2-\frac{(sumX)^2}{n} ]}{[sumY^2-\frac{(sumY)^2}{n} ]} = \frac{0.95^2[7347-\frac{(253)^2}{10} ]}{[13010.75-\frac{(346.50)^2}{10} ]} = 0.86

This means that 86% of the variability of the annual maintenance expense of the computer wheel alignment and balancing machine is explained by the weekly usage under the estimated model ^Y= 10.53 + 0.95X

d)

Without usage, you'd expect the annual maintenance expense to be $1053

If used 100 hours weekly the expected maintenance expense will be 10.53+0.95*100= 105.53 $100s⇒ $10553

If used 1000 hours weekly the expected maintenance expense will be $96053

It is recommendable to purchase the contract only if the weekly usage of the computer is greater than 100 hours weekly.

4 0
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Question 17, 19 and 21 ?
Vaselesa [24]
If this is Textbook work- use SLADER (the app or the website)
3 0
3 years ago
Order these numbers from Least to Greatest 4,209 2,438 4,703 3,026
Virty [35]

2,438 3,026 4,209 4,703

7 0
4 years ago
-56/8=? I dont understand the question help pls​
lisov135 [29]

Answer:

that would be -7

Step-by-step explanation:

3 0
3 years ago
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