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3 years ago

Assignmenti Given A={a,b, c, d], find

Mathematics

1 answer:

REY [17]3 years ago

3 0

9514 1404 393

Answer:

{ }, {a}, {b}, {c}, {d}, {a,b}, {a,c}, {a,d}, {b,c}, {b,d}, {c,d}, {a,b,c}, {a,b,d}, {a,c,d}, {b,c,d}, {a,b,c,d}

Step-by-step explanation:

The number of subsets of a set with n elements is 2^n, including the empty set and the full set. Your subsets are ...

{ }, {a}, {b}, {c}, {d}, {a,b}, {a,c}, {a,d}, {b,c}, {b,d}, {c,d}, {a,b,c}, {a,b,d}, {a,c,d}, {b,c,d}, {a,b,c,d}

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Kevin traveled at a constant speed on the highway from Hickory Hills to Chicago in 20 minutes. The distance from Hickory Hills t

beks73 [17]

Answer: $V=51\ \frac{mi}{h}$

Step-by-step explanation:

You need to used the following formula:

$V=\frac{d}{t}$

Where "V" is the speed, "d" is the distance and "t" is the time.

In this case you know that Kevin traveled at a constant speed on the highway from Hickory Hills to Chicago in 20 minutes (which is $\frac{1}{3}\ h$ ) and the distance is 17 miles. Then, you can identify that:

$t=\frac{1}{3}\ h\\\\d=17\ mi$

Therefore, knowing these values, you can substitute them into the formula. Then, you get:

$V=\frac{17\ mi}{\frac{1}{3}\ h}\\\\V=51\ \frac{mi}{h}$

8 0

3 years ago

A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20. Which state

ololo11 [35]

Given:

A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20.

To find:

The correct statement for the box plot.

Solution:

Lower quartile is 10 and upper quartile is 15, so the box will go from 10 to 15.

Median of the data set is 12, so a line dividing the box will be at 12.

Minimum value is 4 and lower quartile is 10, so the left whisker will go from 4 to 10.

Upper quartile is 15 and maximum value is 20, so the right whisker will go from 15 to 20.

Therefore, the correct option is B.

8 0

3 years ago

Read 2 more answers

Hi Mariceo, when you submit this form, the owner will be able to see your name and email address.

Andreyy89

So you can see my email address? Haha sure...

6 0

3 years ago

(a) If the breadth of rectangle in one-third of its length and perimeter is 80 cm, find the length and breadth of rectangle.

Gwar [14]

Answer:

Length = 30m and Breadth = 10m

Step-by-step explanation:

Given that :

Perimeter = 80 m ;

Breadth = 1/3 of Length ; Length = l

We know that :

Perimeter of rectangle = 2 ( L + B ).

80 = 2 ( L + 1/3 L )

80/2 = 4/3 L.

40 = 4/3 L

3/4 × 40 = L.

3 × 10 = L.

L = 30m.

Breadth = 1/3 of Length.

Breadth = 1/3 × 30.

Breadth = 10m.

5 0

3 years ago

Read 2 more answers

Substitution again help please

Vesnalui [34]

Answer:

Step-by-step explanation:

1) 4x -3

x = -7 ;

4x - 3 = 4*(-7) - 3 = - 28 - 3 = -31

x = 14 ;

4x - 3 = 4*14 - 3 = 56 - 3 = 53

x = 0

4x - 3 = 0 - 3 = -3

2) 6 -3x

x = -7 ;

6 - 3x = 6 - 3*(-7) = 6 + 21 = 27

x = 14

6 - 3x = 6 - 3*14 = 6 - 42 = -36

x = 0

6 - 3x = 6 - 0 = 6

$3) \dfrac{3x - 21}{7}\\\\x = -7\\\\\\\dfrac{3*(-7)-21}{7}=\dfrac{-21-21}{7}=\dfrac{-42}{7}=-6\\\\\\x = 14\\\\\dfrac{3*14-21}{7}=\dfrac{42-21}{7}=\dfrac{21}{7}=3\\\\\\x=0\\\\\dfrac{0-21}{7}=\dfrac{-21}{7}=-3\\\\$

$\dfrac{3x}{7}-21\\\\\\x = -7\\\\\dfrac{3*(-7)}{7}-21=-3-21=-24\\\\\\x =14\\\\\dfrac{3*14}{7}-21=3*2-21=6-21=-15\\\\\\x=0\\\\\dfrac{0}{7}-21=-21$

8 0

2 years ago