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Karolina [17]
3 years ago
9

Explain how to solve (6x^3-1x^2+1) / (2x+1) step by step.

Mathematics
1 answer:
sveta [45]3 years ago
3 0
Sorry i cant.Mabey if you tell me what ^ and - is i  can help
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Explain how to determine if you have a direct variation or proportional relationship
neonofarm [45]

Answer:

straight line that passes through the origin

Step-by-step explanation:

Two variables are said to have a direct variation or proportional relationship if it can be represented by y = kx, where k is a constant.

Comparing this with the equation of a straight line y = mx + b, where m is the slope of the line and b is the y intercept (value of y when x = 0), We can tell if the say that the graph of a direct variation or proportional relationship is a straight line with no y intercept (b = 0, that is it passes through the origin).

8 0
3 years ago
I have trouble understanding word problems. May I please have help with number 15? Thank you very much!
guapka [62]
Basically you do fractions side by side. so, 6/3=15/h and then cross multiply to get your answer so that would give you 3h=80, then divide 80÷3
5 0
2 years ago
Help please. anything would help.
Nataly_w [17]

Answer:

Option a) 1/5 is most closely to 0.

8 0
2 years ago
Read 2 more answers
At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa
11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 7 parts

            r = number of success = fewer than 2

           p = probability of success which in our question is % of defective

                 parts produced by one of the machine, i.e; 19%

<em>LET X = Number of parts that are defective</em>

<u>So, it means X ~ Binom(n = 7, p = 0.19)</u>

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

    P(X < 2) = P(X = 0) + P(X = 1)

                  =  \binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}

                  =  1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}

                  =  <u>0.604</u>

<em>Therefore, the probability that fewer than 2 of these parts are defective is 0.604.</em>

8 0
2 years ago
Round .1325 to the nearest thousandths
faltersainse [42]
0.133 because 5 mean you have to round up so it is 0.133
3 0
3 years ago
Read 2 more answers
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