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dimaraw [331]
2 years ago
10

Given h(x)=3x+4, solve for x when h(x)=1

Mathematics
2 answers:
Dmitrij [34]2 years ago
6 0

Step-by-step explanation:

h(x) = 3x + 4

h(1) = 3(1) + 4

h(1) = 3 + 4

h(1) = 7 ans.

aivan3 [116]2 years ago
3 0

Answer:

7

Step-by-step explanation:

Given,

h ( x ) = 1

To find : -

h ( x ) = 3x + 4

h ( 1 ) = 3 ( 1 ) + 4

= 3 + 4

h ( 1 ) = 7

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Answer:

the answer is 1100..........

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Help what do I do do i just write y-3x+5 or solve it ​
Rina8888 [55]

Answer:

y=-3x+5

Step-by-step explanation: Yes you have it correct. The question is asking for you to put it into an equation that fits the slope and y-intercept which is slope-intercept form. Additional note, when you have a problem like this and it doesn't say what type of equation form to put it in, put it in slope-intercept form for simplicity's sake.

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1 year ago
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How do you solve the inequality 6y+3&gt; -18x
Alex17521 [72]
6y + 3 \ \textgreater \  - 18 x

Subtract 3 from both sides:

6 y + 3 - 3 \ \textgreater \  - 18 x - 3

6y \ \textgreater \  - 18 x - 3

Dividade both sides by 6 :

\frac{6y}{6} \ \textgreater \   \frac{-18x-3}{6}

y \ \textgreater \  \frac{-18x-3}{6}

hope this helps!


6 0
2 years ago
What is the difference? 2x 7 - 8x 7<br> a. -6x 14<br> b. 10x 7<br> c. -16x 7<br> d. -6x 7
spayn [35]
2x^{7}-8x^{7}=-6x^{7}
5 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
Sholpan [36]

Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

or

b > 3\frac{2}{15}\\\\

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

2 & 3/5 = (2*5 + 3)/5

2 & 3/5 = (10 + 3)/5

2 & 3/5 = 13/5

The inequality 2 \frac{3}{5} < b - \frac{8}{15}\\\\ is the same as \frac{13}{5} < b - \frac{8}{15}\\\\

---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

7 0
3 years ago
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