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2 years ago

Simplify this expression.

Mathematics

1 answer:

lina2011 [118]2 years ago

5 0

7.82ksknznsjsjjjjjjj

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Find the derivatives of the following implicit function

ddd [48]

Answer:

$\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

Step-by-step explanation:

$3x^2-6xy+y^2=2x-y\\\mathrm{Treat\:}y\mathrm{\:as\:}y\left(x\right)\\\mathrm{Differentiate\:both\:sides\:of\:the\:equation\:with\:respect\:to\:}x\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=\frac{d}{dx}\left(2x-y\right)\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(2x-y\right)=2-\frac{d}{dx}\left(y\right)\\6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)=2-\frac{d}{dx}\left(y\right)$

$\mathrm{For\:convenience,\:write\:}\frac{d}{dx}\left(y\right)\mathrm{\:as\:}y^{'\:}\\6x-6\left(y+xy^{'\:}\right)+2yy^{'\:}=2-y^{'\:}\\\mathrm{Isolate}\:y^{'\:}:\quad y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\\mathrm{Write}\:y^{'\:}\:\mathrm{as}\:\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}$

3 0

3 years ago

INSERT TWO RATIONAL NUMBERS BETWEEN 2 AND 3. How to find them?

Kay [80]

There are an infinite number of them.
Here are a few:

2.1
2.2
2.3
2.3000000001
2.30000000000000006
2.5
2.00009
.
.
etc.

How to find them:

You probably never heard this before, but I'll bet
you'll remember it from now on:

<em>ANY number that you can write down on paper completely, </em><em>using digits
and a decimal point if you need it but no symbols, is a rational number.</em>

If you can write it down completely without any 'comments', then it's rational.

3 0

3 years ago

Select the correct answer

UkoKoshka [18]

Ans

i cant see the pic

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Katie earns 15$ each hour. Round to total time katie worked to the nearest hour and estimate her pay by using mulitplacation

Cloud [144]

Answer:

How long did she work for though?

Step-by-step explanation:

3 0

2 years ago

The total cost of 7 shirts and 5 pairs of pants is $517. The total cost of a shirt and a pair of pants is $89. How much does a p

pickupchik [31]

Answer:

pair of pants = $53

Step-by-step explanation:

s = shirts

p = pair of pants

eq = equation

eq 1: 7s + 5p = 517

eq 2: s + p = 89

multiply the equation 2 by 7

eq 3: 7s + 7p = 623

negate equation 1 and add it to the eq 3

7s + 7p = 623

+ -7s - 5p = -517

2p = 106

p = 53

7 0

2 years ago