Stop with the links don’t work
<h3>
ax² + bx + c = 0</h3>
<em>Let's write -9 where we see A</em><em>:</em>
<h3>
-9x² + bx + c = 0</h3>
<em>Let's</em><em> </em><em>write</em><em> </em><em>0</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>B</em><em>:</em>
<h3>
-9x² + 0.x + c = 0</h3>
<em>(</em><em>Since B = 0, when it is multiplied by x, it becomes 0 again</em><em>)</em>
<h3>
-9x² + c = 0</h3>
<em>Let's</em><em> </em><em>write</em><em> </em><em>-2</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>C</em><em>:</em>
<h3>
-9x² + -2 = 0</h3>
<em>Now we can move on to solving our equation</em><em>:</em><em>)</em>
<em>Let's put the known and the unknown on different sides:</em>
<em>(</em><em>-2 goes to the opposite side positively</em><em>)</em>
<h3>
-9x² = 2</h3>
<em>(</em><em>i</em><em>t goes as a division because it is in the case of multiplying -9 across</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
<h3>
x² = 2/-9</h3>
<em>I could not find the rest of it, but I did not want to delete it for trying very hard. Sorry. It felt like we should take the square root, but I couldn't find it, maybe this can help you a little bit.</em>
<em>Please do not report</em><em>:</em><em>(</em>
<em>I hope I got it right, I'm trying to improve my English a little :)</em>
<h3>
<em>Greetings from Turke</em><em>y</em><em>:</em><em>)</em></h3>
<h3>
<em><u>#XBadeX</u></em></h3>
The answer for ur question is C..
HOPE THIS HELPS
^_^ HAPPY TO HELP YA ^_^
With
a standard deviation of 6 minutes, we will test the hypothesis that σ = 6
against the alternative that σ < 6 if a random sample of the test
times of 20 high school seniors has a standard deviation s = 4.51. use a
0.05 level of significance.
<span /><span><span>
</span></span>
1/50? I can’t be sure....
Ok, so.. first you write both the problems down and write the 10 as a fraction (so it would automatically be 10/1). Then invert so it would be a multiplication problem (1/5 x 1/10). Since you can’t cross cancel, you multiply across. So, 1/5 x 1/10 (1 x 1 and 10 x 5)
1/50
