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Rudik [331]
3 years ago
9

Describe the transformation in g (x) = (-5/8x) as it relates to the graph of the parent function.​

Mathematics
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

reflection over x axis then horizontal stretch by factor of 8/5

Step-by-step explanation:

f(x)=x

h(x) = -f(x)  ... reflection over x axis   (x,y) -> (x,-y)

-f(x) -> g(x) = (-5/8x) ...0 < |5/8| <1  ... horizontal stretch   (x,-y) -> (x / (5/8) , -y)

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marissa [1.9K]

the answer is A 2.3

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7 0
4 years ago
Determine which number has a lesser magnitude.<br> a<br> -4 and -5
Stells [14]

Answer:   -4

This is because -4 is closer to 0 on the number line, when compared to -5.

You are basically measuring the distances from 0 to determine magnitude.

4 0
3 years ago
What are the equations of the asymptotes of the graph of f(x)=(5/x+7)−8 ?
ludmilkaskok [199]

Answer:

\mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-1

The graph of the function is also attached.

Step-by-step explanation:

Considering the expression

\:f\left(x\right)=\left(\frac{5}{x}+7\right)-8\:\:

\mathrm{Simplify}\:\frac{5}{x}+7-8:\quad \frac{5}{x}-1

\mathrm{Vertical\:asymptotes\:of\:}\frac{5}{x}-1:

Go over every undefined point x = a and check if at least one of the following statement is true.

\lim _{x\to a^-}f\left(x\right)=\pm \infty

\lim _{x\to a^+}f\left(x\right)=\pm \infty

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{5}{x}-1\mathrm{\:and\:compare\:to\:zero}

x=0

The following points are undefined

x=0

\mathrm{The\:vertical\:asymptotes\:are:}

x=0

\mathrm{Horizontal\:Asymptotes\:of\:}\frac{5}{x}-1:

\mathrm{Check\:if\:at\:}x\to \pm \infty \mathrm{\:the\:function\:}y=\frac{5}{x}-1\mathrm{\:behaves\:as\:a\:line,\:}y=mx+b

\mathrm{Find\:an\:asymptote\:for\:}x\to -\infty \::

\lim _{x\to -\infty \:}\frac{f\left(x\right)}{x}=\lim _{x\to -\infty \:}\frac{\frac{5}{x}-1}{x}=0

\lim _{x\to -\infty \:}f\left(x\right)-mx=\lim _{x\to -\infty \:}\frac{5}{x}-1-0x=-1

y=-1

\mathrm{Find\:an\:asymptote\:for\:}x\to \infty:

\lim _{x\to \infty \:}\frac{f\left(x\right)}{x}=\lim _{x\to \infty \:}\frac{\frac{5}{x}-1}{x}=0

\lim _{x\to \infty \:}f\left(x\right)-mx=\lim _{x\to \infty \:}\frac{5}{x}-1-0x=-1

y=-1

\mathrm{The\:horizontal\:asymptote\:is:}

y=-1

Therefore,

\mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-1

The graph of the function is also attached.

6 0
4 years ago
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13 is the answer if I'm correct
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3 years ago
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15 points!! Will give brainliest for smartest answer!
ivann1987 [24]

Answer:

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Step-by-step explanation:

since she is trying to keep it under 40 each month and there is a flat fee of 34$ she will have 6$ left then you just have to divide so you will do 6/0.05

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3 years ago
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