1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
seropon [69]
2 years ago
14

HELP!!!!!!!!!!!

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
7 0

Using the mean concept, it is found that:

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

-----------------------

The mean of a data-set is given by the <u>sum of all observations divided by the number of observations</u>.

In this problem:

  • The data-set is her swim time relative to her goal, which is: {1.25, -1, 2.25, 0, -2.}
  • 5 observations.

Thus, the mean is:

M = \frac{1.25 - 1 + 2.25 + 0 - 2}{5} = 0.1

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

A similar problem is given at brainly.com/question/24787716

You might be interested in
How can I do this exercise? <img src="https://tex.z-dn.net/?f=%5Cfrac%7B-2%7D%7B12%7D%20%3D%20%5Cfrac%7Bx%20%2B%201%7D%7Bx%20%2B
matrenka [14]

Answer:

-8/7 =x

Step-by-step explanation:

-2         x+1

----- = -----------

12         x+2

Using cross products

-2 (x+2) = 12 (x+1)

Distribute

-2x -4 = 12x+12

Add 2x to each side

-2x+2x -4 = 12x+2x+12

-4 = 14x +12

Subtract 12 from each side

-4-12 = 14x

-16 = 14x

Divide each side by 14

-16/14 =14x/14

-8/7 =x

3 0
3 years ago
25. A wheelchair access ramp has an angle of elevation of 16°. If the ramp
Elanso [62]

Answer:

C. 76.81

Step-by-step explanation:

We must use one of the trigonometric ratios to find the length, L,  of the ramp.  If we use 16 as the reference angle, the 22 in would be our opposite side and the ramp length is the adjacent.

Therefore, we must use tan, which is \frac{opposite}{adjacent}:

tan (16)=\frac{22}{L} \\\\L*(tan(16)=22)\\\\L*tan(16)=22\\

\frac{L*tan(16)}{tan(16)}=\frac{22}{tan(16}  \\\\L=79.815=79.82 in.

8 0
1 year ago
Please help, thank you!!
julsineya [31]

Answer:

Step-by-step explanation:

Givens

  • Triangle
  • Base = 11  inches
  • Height = 12 inches

Formula

A = Base * height / 2

Solution

  • Area = 11 * 12/2
  • Area = 132 /2
  • Area = 66 square inches.
4 0
3 years ago
Read 2 more answers
15 points PLEASE HELP!!!<br><br> Factor the following equation:<br> <img src="https://tex.z-dn.net/?f=x%5E2%2B3x%2B4" id="TexFor
ycow [4]

Step-by-step explanation:

x²+3x+4=0

x²+3x_ +2=0

x²+3x_2=-2

x²+3x_2+(3x_4)²=-2+(3/4)²

(x+3/4) =-2+9_16

x+3_4 = -32+9__16 =√-23_6

x+3_4 =-√23_4

x = -3+√-23___4

x = -3- √-23___4 , -3+√-23___4 //

Mark my answer as branlist answer

follow me on my another account "sarivigakarthi"

5 0
2 years ago
Least common multiple of 9(x+2)(2x-1) and 3x+2
mixas84 [53]

Answer:

LCM(9, -1, -1, +2, +2, +2) = 2×3^2 = 18

Step-by-step explanation:

9 = 32

-1 = -1

-1 = -1

+2 = 2

+2 = 2

+2 = 2

LCM = 2×3^2 = 18

18 / 9 = 2

18 / -1 = -18

18 / -1 = -18

18 / +2 = 9

18 / +2 = 9

18 / +2 = 9

3 0
3 years ago
Other questions:
  • × - 2/3=7<br><br> Enter your answer in the box : <br><br> Hurry plz
    9·2 answers
  • 1._Polynomials_Putting_Pieces_Together.pdf
    8·1 answer
  • PLEASE HELP NOW 25pts!! O 60x10
    11·1 answer
  • The sum n of three consecutive even integers is 54, What is the smallest integer being added?
    8·1 answer
  • The sum of two numbers is 9. And the sum of their reciprocals is 1/2.find the numbers
    12·1 answer
  • If f(x)=3x^2+15, what is the value of f(4).
    8·2 answers
  • Which question can be answered by finding 1 1/4 divided by 1/2
    11·2 answers
  • Anyone know this Geometry problem?
    11·1 answer
  • After factoring out the effect of other variables known to affect SAT, such as socioeconomic status, researchers found that musi
    11·1 answer
  • What type of triangle center is shown as point C in the figure?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!