Question

Pls help ASAP I’ll give brainliest

Answer 1

Answer:

• (A) 44.7°

Step-by-step explanation:

Use the law of cosines:

• $cos A=(b^2+c^2-a^2)/(2bc)$
• $cos A=(25^2+31^2-22^2)/(2*25*31)=0.711$
• m∠A = arccos(0.711) ≈ 44.7°

Answer 2

Using law of cosines

$\\ \sf\longmapsto cosA=\dfrac{b^2+c^2-a^2}{2bc}$

$\\ \sf\longmapsto cosA=\dfrac{25^2+31^2-32^2}{2(25)(31)}$

$\\ \sf\longmapsto cosA=\dfrac{625+961-484}{1550}$

$\\ \sf\longmapsto cosA=\dfrac{1102}{1550}$

$\\ \sf\longmapsto cosA=0.7109$

$\\ \sf\longmapsto A=cos^{-1}(0.7109)$

$\\ \sf\longmapsto A=44.7°$