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Marysya12 [62]
2 years ago
5

Are these fractions equivalent or nonequivalent? 9/14 2/11

Mathematics
1 answer:
saw5 [17]2 years ago
6 0
They would be <span>nonequivalent. </span>
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Factor the expression: x^6-729. Show your work Please.
Brut [27]

Answer:

  • (x + 3)(x - 3)(x^2 -3x + 9)(x^2 + 3x + 9)

Step-by-step explanation:

<u><em>Use of formulas:</em></u>

  • <em>a^2 - b^2 = (a + b)(a -b)</em>
  • <em>a^3 + b^3 = (a + b)(a^2 - ab + b^2)</em>
  • <em>a^3 - b^3 = (a - b)(a^2 + ab + b^2)</em>

<u>Given the expression: </u>

  • x^6-729

<u>Factoring 729</u>

  • 729 = 3*3*3*3*3*3 = 3^6

<u>Factoring the expression </u>

  • x^6 - 3^6 =
  • (x^3)^2 - (3^3)^2 =
  • (x^3 + 3^3)(x^3 - 3^3) =
  • (x + 3)(x^2 -3x + 9)(x - 3)(x^2 + 3x + 9) =
  • (x + 3)(x - 3)(x^2 -3x + 9)(x^2 + 3x + 9)
7 0
3 years ago
Angie is canning applesauce for the winter. She has a can that is 6 inches high and 4 inches in diameter. How much applesauce ca
KonstantinChe [14]

Answer:

Idk

Step-by-step explanation:

6 0
3 years ago
How many terms are in -7k+x2-3
liq [111]

Answer: 2 terms 1:k 2:x

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Write an equation in slope-intercept form of the line.
alexira [117]

Answer:

y=x-3

Step-by-step explanation:

To find slope, use m=y2-y1/x2-x1, using values of x and y from two different points. Once you have found slope, take another point and use the point-slope equation y-y1=m(x-x1) and substitute in slope for m and the point for x1 and y1. Isolate y by subtracting y1 from both sides.

3 0
2 years ago
In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=3 and BC=2, what is
Alex777 [14]

Answer:

<em>The area of the shaded region is 3.</em>

Step-by-step explanation:

Since point E lies halfway between AB and BC, the area of the shaded region (As) consists of two identical triangles with base equal to AB and height equal to half the measure of BC:

A_s=2 * A_t

Where At is the area of each triangle.

\displaystyle A_t=\frac{AB*BC/2}{2}

\displaystyle A_t=\frac{AB*BC}{4}

We know AB=3 and BC=2, thus:

\displaystyle A_t=\frac{3*2}{4}=\frac{6}{4}

Simplifying:

\displaystyle A_t=\frac{3}{2}

Finally:

\displaystyle A_s=2 * \frac{3}{2}

A_s=3

The area of the shaded region is 3.

Note the area of the shaded region is half the area of the rectangle.

3 0
2 years ago
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