Figures of same shape and size are similar .Two circles C1&C2 will be similar.
Circle 1 has a center of (-4,5) and circle 2 has a center of (2,1) .The x of the center is having the translation x+6 and the y is having a translation of y-4.The center of the circle is dilated by 3 units.
The circles are similar because you can translate Circle 1 using the transformation rule (x+6,y-4 ) and then dilate it using a scale factor of 3.
2) Area of sector = 
÷360.
Where α is the angle made at center.
Area of given sector= π(12)(12)(60)÷360 =24π.
Answer:
Area of the circle = 
Step-by-step explanation:
Circumference = 
Circumference of the circle = 
As,
Area of a circle = 
Answer:
False
Step-by-step explanation:
The statement is False, because the average value of a funciton f(x) on an interval is given by the value of the integral of the function on that interval divided by its length. In this case, the integral is right, but we are not integrating exactly f, and thats why the average value is not given correctly.
Answer:
√(p²-4q)
Step-by-step explanation:
Using the Quadratic Formula, we can say that
x = ( -p ± √(p²-4(1)(q))) / 2(1) with the 1 representing the coefficient of x². Simplifying, we get
x = ( -p ± √(p²-4q)) / 2
The roots of the function are therefore at
x = ( -p + √(p²-4q)) / 2 and x = ( -p - √(p²-4q)) / 2. The difference of the roots is thus
( -p + √(p²-4q)) / 2 - ( ( -p - √(p²-4q)) / 2)
= 0 + 2 √(p²-4q)/2
= √(p²-4q)
Answer:
2,5 maybe
Step-by-step explanation:
