1. Let the first integer be represented by: 2k
the second integer by: 2(k+1)
the third integer by: 2(k+2)
and the fourth by: 2(k+3)
Then, 2k + 2(k+2) = 2(k+3) - 6
2k + 2k + 4 = 2k + 6 - 6
4k + 4 = 2k
4 = -2k
-2 = k
Answer: -4, -2, 0, 2
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2. Let the first integer be represented by: 2k+1
the second integer by: 2k+3
the third integer by: 2k+5
and the fourth by: 2k+7
Then, 2k+7 = (2k+1) + (2k+3) + (2k+5) + 2
2k + 7 = 6k + 11
-4 = 4k
-1 = k
Answer: -1, 1, 3, 5
<span>6.16×10^6
10^6 = </span>10000006.16 x 1000000 = <span>6160000
</span><span>6,160,000 is your answer
</span>
hope this helps
<h3>
Answer: 29,030,400</h3>
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Explanation:
Let's say the mother will temporarily take the place of all the sisters. Wherever the mother sits will represent the block of girls.
Taking out the 6 sisters and replacing them with the mother leads to 7+1 = 8 people in a line.
There are 8! = 8*7*6*5*4*3*2*1 = 40,320 different ways to arrange 8 people.
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Again, the mother's position is where the sisters block will go. So let's say the mother was in seat #2. This would mean one brother would take seat #1, and all of the sisters would take the next six seats, until we reach seat #7 is when another brother would take the next seat.
Within any given permutation (the 40320 mentioned), there are 6! = 6*5*4*3*2*1 = 720 different ways to arrange just the girls in that girls block/group.
All together, there are 40320*720 = 29,030,400 different ways to arrange the 13 siblings where all the girls are seated together.
Answer:
100+150
Step-by-step explanation:
(50x2)+(50x3)
100+150
250
