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Tcecarenko [31]
2 years ago
10

Use deductive reasoning to select a valid conclusion. If a quadrilateral is a rhombus, then it is also a parallelogram. Quadrila

teral ABCD is a rhombus.A. Quadrilateral WXYZ is a rhombusB. No valid conclusionC. Quadrilateral ABCD is a parallelogramD. Every quadrilateral is a rhombus
Mathematics
1 answer:
My name is Ann [436]2 years ago
5 0

Answer:

No valid conclusion

Step-by-step explanation:

- All rhombuses are parallelograms

- Not all parallelograms are rhombuses because a rhombus has four equal-length sides and a parallelogram has equal opposite sides.

- all squares are rhombuses but not all rhombuses are squares because a square has 4 right angles (90 degrees) and a rhombus has equal opposite angles

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Help me with this problem, i have to simply this ratio
Elena-2011 [213]
Keep on dividing them both by 2
4 0
3 years ago
For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0.
iragen [17]

Answer:

-\frac{7}{3}

Step-by-step explanation:

To solve this, we are using the average rate of change formula:

m=\frac{f(b)-f(a)}{b-a}

where

m is the average rate of change

a is the first point

b is the second point

f(a) is the function evaluated at the first point

f(b) is the function evaluated at the second point

We want to know the average rate of change of the function f(x)=0.5^x-6 form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, a=-3 and b=0.

Replacing values

m=\frac{f(b)-f(a)}{b-a}

m=\frac{0.5^0-6-(0.5^{-3}-6)}{0-(-3)}

m=\frac{1-6-(8-6)}{3}

m=\frac{-5-(2)}{3}

m=\frac{-5-2}{3}

m=\frac{-7}{3}

m=-\frac{7}{3}

We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is -\frac{7}{3}

4 0
2 years ago
8+w/4 when w is 16<br> plz answer it for me plzzz
Marat540 [252]

Answer:

  1. 8+w/4
  2. Putting w = 16
  3. 8+16/4
  4. (32+16)/4
  5. = 48/4
  6. = 12

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

6 0
2 years ago
What is the component form of the vector represented by 2a when a⃗ =〈−2,3〉?
Paladinen [302]

Answer:

\vec v = 2\cdot \vec a = \langle -4,6 \rangle

Step-by-step explanation:

Let \vec a = \langle -2, 3 \rangle, we need to determine \vec v = 2\cdot \vec a, which can be found by applying the following property:

\alpha \cdot \langle x,y \rangle = \langle \alpha \cdot x, \alpha \cdot y\rangle, \forall \,\alpha,x,y\in \mathbb{R} (1)

Then,

\vec v = 2\cdot \langle -2,3 \rangle

\vec v = \langle -4,6 \rangle

8 0
2 years ago
Create an equivalent expression by simplifying the expression below.
BabaBlast [244]

Answer:

see explanation

Step-by-step explanation:

Given

- \frac{1}{2} [ - \frac{3}{2} c + 6c + 1 ] - 3c

Distribute the square bracket by - \frac{1}{2}

= \frac{3}{4} c - 3c - \frac{1}{2} - 3c ← combine like terms

= \frac{3}{4} c - 6c - \frac{1}{2}

= \frac{3}{4} c - \frac{24}{4} c - \frac{1}{2}

= - \frac{21}{4} c - \frac{1}{2}

6 0
2 years ago
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