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Tcecarenko [31]

2 years ago

10

Use deductive reasoning to select a valid conclusion. If a quadrilateral is a rhombus, then it is also a parallelogram. Quadrila

teral ABCD is a rhombus.A. Quadrilateral WXYZ is a rhombusB. No valid conclusionC. Quadrilateral ABCD is a parallelogramD. Every quadrilateral is a rhombus

1 answer:

My name is Ann [436]2 years ago

5 0

Answer:

No valid conclusion

Step-by-step explanation:

- All rhombuses are parallelograms

- Not all parallelograms are rhombuses because a rhombus has four equal-length sides and a parallelogram has equal opposite sides.

- all squares are rhombuses but not all rhombuses are squares because a square has 4 right angles (90 degrees) and a rhombus has equal opposite angles

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Elena-2011 [213]

Keep on dividing them both by 2

4 0

3 years ago

For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0.

iragen [17]

Answer:

$-\frac{7}{3}$

Step-by-step explanation:

To solve this, we are using the average rate of change formula:

$m=\frac{f(b)-f(a)}{b-a}$

where

$m$ is the average rate of change

$a$ is the first point

$b$ is the second point

$f(a)$ is the function evaluated at the first point

$f(b)$ is the function evaluated at the second point

We want to know the average rate of change of the function $f(x)=0.5^x-6$ form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, $a=-3$ and $b=0$ .

Replacing values

$m=\frac{f(b)-f(a)}{b-a}$

$m=\frac{0.5^0-6-(0.5^{-3}-6)}{0-(-3)}$

$m=\frac{1-6-(8-6)}{3}$

$m=\frac{-5-(2)}{3}$

$m=\frac{-5-2}{3}$

$m=\frac{-7}{3}$

$m=-\frac{7}{3}$

We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is $-\frac{7}{3}$

4 0

2 years ago

8+w/4 when w is 16<br> plz answer it for me plzzz

Marat540 [252]

Answer:

8+w/4
Putting w = 16
8+16/4
(32+16)/4
= 48/4
= 12

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

6 0

2 years ago

What is the component form of the vector represented by 2a when a⃗ =〈−2,3〉?

Paladinen [302]

Answer:

$\vec v = 2\cdot \vec a = \langle -4,6 \rangle$

Step-by-step explanation:

Let $\vec a = \langle -2, 3 \rangle$ , we need to determine $\vec v = 2\cdot \vec a$ , which can be found by applying the following property:

$\alpha \cdot \langle x,y \rangle = \langle \alpha \cdot x, \alpha \cdot y\rangle$ , $\forall \,\alpha,x,y\in \mathbb{R}$ (1)

Then,

$\vec v = 2\cdot \langle -2,3 \rangle$

$\vec v = \langle -4,6 \rangle$

8 0

2 years ago

Create an equivalent expression by simplifying the expression below.

BabaBlast [244]

Answer:

see explanation

Step-by-step explanation:

Given

- $\frac{1}{2}$ [ - $\frac{3}{2}$ c + 6c + 1 ] - 3c

Distribute the square bracket by - $\frac{1}{2}$

= $\frac{3}{4}$ c - 3c - $\frac{1}{2}$ - 3c ← combine like terms

= $\frac{3}{4}$ c - 6c - $\frac{1}{2}$

= $\frac{3}{4}$ c - $\frac{24}{4}$ c - $\frac{1}{2}$

= - $\frac{21}{4}$ c - $\frac{1}{2}$

6 0

2 years ago