Answer:
406
Step-by-step explanation:
Five consecutive positive integers = x, (x+1), (x+2), (x+3), (x+4)
x + (x+1) + (x+2) + (x+3) + (x+4) = 2020
5x + 10 = 2020
5x = 2020-10
5x = 2010
x = 2010÷5
x = 402
The largest of the number is = x+4
x+4 = 402 + 4 = 406
Answer:
b
Step-by-step explanation:
Answer:
1/9
Step-by-step explanation:
120/1080 can be simplified to 1/9
First we make the fractions homonym ( they must have the same denomitator)
0.6 = 6 / 10 7/9
6/10 = 6 * 9 / 10 * 9 = 54 / 90 7/9 = 7 * 10 / 9 * 10 = 70 / 90
The numbers which are between these numbers are ;
55 / 90 , 56 / 90 , 57 / 90 , 58 / 90 , 59 / 90, 60 / 90 , 61 / 90 , 62 / 90 , 63 / 90 , 64 / 90, 67 / 90 , 68 / 90 , 69 / 90
62 / 90 = 62 / 2 / 90 /2 = 31 / 45
So the right answer is B.
Hope that helps :)
-50m^4 n^7 = 10m^2n^7(-5m^2)<span>
and
40m^2 n^10 = 10</span>m^2 n^7(4n^3)
Answer: GCF = 10m^2 n^7
