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Elan Coil [88]
3 years ago
13

Solve for area and perimeter. Show your work please

Mathematics
1 answer:
otez555 [7]3 years ago
6 0

Answer:

Area = 18x + 12

Perimeter = 6x -4 + 12

Step-by-step explanation:

Area = L × W

so, Area = 3x-2×6, which we can write as;

Area = 6(3x-2), which will be;

Area = (6×3x) + (6×(-2))

Area = 18x + (-12), where (+) and (-) will give you (-), so;

Area = 18x - 12

Perimeter(P) = 2(L+W)

P = 2(3x-2+6), which will be;

P= (2×3x) + (2×(-2) + (2×6)

P = 6x + (-4) + 12

P = 6x - 4 + 12

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2x^2 + 2y^2 - 8x + 10y + 2 =0
scoray [572]

A circle of radius <em>r</em> centered at (<em>a</em>, <em>b</em>) has equation

(<em>x</em> - <em>a</em>)² + (<em>y</em> - <em>b</em>)² = <em>r </em>²

To get the given equation in this form, complete the square with respect to both <em>x</em> and <em>y</em>.

2<em>x</em>² - 8<em>x</em> = 2 (<em>x</em>² - 4<em>x</em>)

2<em>x</em>² - 8<em>x</em> = 2 (<em>x</em>² - 4<em>x</em> + 4 - 4)

2<em>x</em>² - 8<em>x</em> = 2 ((<em>x</em> - 2)² - 4)

2<em>x</em>² - 8<em>x</em> = 2 (<em>x</em> - 2)² - 8

2<em>y</em>² + 10<em>y</em> = 2 (<em>y</em>² + 5<em>y</em>)

2<em>y</em>² + 10<em>y</em> = 2 (<em>y</em>² + 5<em>y</em> + 25/4 - 25/4)

2<em>y</em>² + 10<em>y</em> = 2 ((<em>y</em> + 5/2)² - 25/4)

2<em>y</em>² + 10<em>y</em> = <u>2 (</u><u><em>y</em></u><u> + 5/2)² - 25/2</u>

So we have

2<em>x</em>² + <u>2</u><u><em>y</em></u><u>²</u> - 8<em>x</em> + <u>10</u><u><em>y</em></u> + 2 = 0

2 (<em>x</em> - 2)² - 8 + <u>2 (</u><u><em>y</em></u><u> + 5/2)² - 25/2</u> + 2 = 0

2 (<em>x</em> - 2)² + 2 (<em>y</em> + 5/2)² = 37/2

(<em>x</em> - 2)² + (<em>y</em> + 5/2)² = 37/4

(<em>x</em> - 2)² + (<em>y</em> + 5/2)² = ((√37)/2)²

which means this circle has radius (√37)/2 and center (2, -5/2).

8 0
3 years ago
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