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ahrayia [7]
3 years ago
14

Solve the following for A:

Mathematics
1 answer:
IrinaK [193]3 years ago
4 0
A(b-c) + 4 = e
take 4 to other side
A(b-c) = e-4
now divide both sides by (b-c)
A = (e-4)/(b-c)



Mark brainliest
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If F(x)=3x/5+3, which of the following is the inverse of F(x)?
Hatshy [7]
Y = 5(x-3)/3

To find this, set up the equation as so:

3y/5 + 3 = x

Then, proceed to solve the two-step equation:

3y/5 = x - 3
3y = 5 (x - 3)
y = 5 (x - 3) / 3

Hope this helps!
6 0
3 years ago
Read 2 more answers
X = y - 3
forsale [732]
To solve this system of equations, start by plugging your equation for x wherever x appears in your second equation, giving you (y-3)+3y=13. Now, combine like terms, (y-3)+3y=13 => 4y-3=13, solve for y by adding 3, 4y-3=12 => 4y=16, divide by 4, 4y=16 => y=4. Now that you have your y value, plug it into the equation for x to get the x value, x=y-3=4-3=1. This makes your solution (1,4), answer choice A
4 0
3 years ago
Claire says the expression 8x’has three terms: 8, x, and 3. Is she correct? Explain.
KatRina [158]

Answer:

No

Step-by-step explanation:

No because the 8x^3 is all one term since it is not separated by any signs.

8 0
3 years ago
Give the domain and range of the relation.
igor_vitrenko [27]

Answer:  A Domain: {-5, 0, 4, 6} Range: {-9,0, 9, 13}

Step-by-step explanation:

Domain is the x-values, least to greatest.

Range is the y-values, least to greatest.

6 0
3 years ago
What is the midpoint coordinates of segment HX H(13,8) X(-6,-6)
Setler79 [48]
Midpoint of (x1,y1) and (x2,y2) is

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

so the midpoint of HX is the mdpoint of (13,8) and (-6,-6)
which is

(\frac{13-6}{2},\frac{8-6}{2}=
(\frac{7}{2},\frac{2}{2}=
(3.5,1)

the midpoint is (3.5,1)
7 0
4 years ago
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