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3 years ago

What kind of solution is -6(x-2)=-7(x-3)

Mathematics

2 answers:

sergij07 [2.7K]3 years ago

7 0

Answer:

Step-by-step explanation:

-6(x-2)=-7(x-3)

-6x + 12 = -7x + 21

-6x + 7x = 21 - 12

x = 9

Firlakuza [10]3 years ago

6 0

Answer:

-6(x-2)=-7(x-3) = False x = 9

Step-by-step explanation:

Solve for x:

-6 (x - 2) = -7 (x - 3)

Expand out terms of the left hand side:

12 - 6 x = -7 (x - 3)

Expand out terms of the right hand side:

12 - 6 x = 21 - 7 x

Add 7 x to both sides:

7 x - 6 x + 12 = (7 x - 7 x) + 21

7 x - 7 x = 0:

7 x - 6 x + 12 = 21

7 x - 6 x = x:

x + 12 = 21

Subtract 12 from both sides:

x + (12 - 12) = 21 - 12

12 - 12 = 0:

x = 21 - 12

21 - 12 = 9:

Answer: x = 9

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3 years ago

One of our brainliest, Konrad509, made this:

Reil [10]

$\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x$

A=10, B=11, C=12, etc.

$\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2$

$121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0$

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that $x\in\mathbb{N}$ . Moreover we can deduce that $x\geq19$ since there is $J$ and $J=19$ .