Answer:
1. 
2. 
3. 
Step-by-step explanation:
Given information:


(1)
We need to find the value of P(s₁|I).





Therefore the value of P(s₁|I) is
.
(2)
We need to find the value of P(s₂|I).





Therefore the value of P(s₂|I) is
.
(3)
We need to find the value of P(s₃|I).





Therefore the value of P(s₃|I) is
.
To solve for x we can use trigonometry since the triangle above is right triangle.
In this problem, it would be the easiest to use the TOA ratio which means the tangent of 62 equals x/40. To get x alone, we can multiply both sides by 40 leaving us with:
x = tan. 62 x 40
x = 1.88072646535 x 40
x = <span>75.229058614
Final Answer: x is around 75 yards</span>
(A) For x representing the cost of one of Tanya's items, her total purchase cost 5x. The cost of one of Tony's items is then (x-1.75) and the total of Tony's purchase is 6(x-1.75). The problem statement tells us these are equal values. Your equation is ...
... 5x = 6(x -1.75)
(B) Subtract 5x, simplify and add the opposite of the constant.
... 5x -5x = 6x -6·1.75 -5x
... 0 = x -10.50
... 10.50 = x
(C) 5x = 5·10.50 = 52.50
... 6(x -1.75) = 6·8.75 = 52.50 . . . . . the two purchases are the same value
(D) The individual cost of Tanya's iterms was $10.50. The individual cost of Tony's items was $8.75.
Answer:
Option b. Two solutions
Step-by-step explanation:
In order to find how many real number solutions the equation has we have to solve it
Given equation: -4x² + 10x + 6 = 0
taking 2 common from the equation
2(-2x² + 5x + 3) = 0
-2x² + 5x + 3 = 0
taking minus sign common from the above equation
2x² - 5x - 3 = 0
We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²
2x² - 6x + x - 3 = 0
taking common above
2x(x-3) + 1(x-3) = 0
taking (x-3) common
(2x+1)(x-3) = 0
2x + 1 = 0
2x = -1
x = 
x - 3 = 0; x = 3
the solutions are

Both values are real numbers, therefore correct option is b
Answer:

Step-by-step explanation:
percentage of graduates with loan = 62%
total sample = 50
Number of student in the sample with student loan
= (percentage of graduates with loan) x (total sample)
= 62% x 50
= 31
Proportion of student in the sample with student loan = 