Answer: shut up nerd you wont report me you goodie toshoos
Step-by-step explanation:
The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
<span>3.12
First, write an equation to express what you know.
g = number of girls
b = number of boys
b * 2.52 + g * x = 2.88(b+g)
Solve for x, first substitute known values for g and b
12 * 2.52 + 18 * x = 2.88(12+18)
Add and multiply what you already know
30.24 + 18x = 86.4
Subtract 30.24 from both sides
18x = 56.16
Divide both sides by 18
x = 3.12
Therefore the GPA of the girls is 3.12</span>
52-46=6 drop down the 1 = 61- 46=15 drop down the 0 =150 46x3= 138 so 150-138= 12
