(x^2)/a^2+(y^2)/b^2=1
a>b
a=6, a^2=36
foci=(a^2-b^2)^(1/2)
4=(36-b^2)^(1/2)
16=36-b^2
b^2=36-16
b^2=20
b=2(5)^(1/2) or (20)^(1/2)
1=(x^2/36)+(y^2/20)
Answer:the error is when 6y=12
Step-by-step explanation:
the original problem says 4x-6y=12
so when you get rid of the 4x, it should still be -6y not positive
The answer is 67/20
Decimal form is 3.35
Answer:
A midsegment (or midline)
Step-by-step explanation:
In geometry, a line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line between its endpoints. A closed line segment includes both endpoints, while an open line segment excludes both endpoints; a half-open line segment includes exactly one of the endpoints.
