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andreev551 [17]
3 years ago
7

Please help.... fast​

Mathematics
2 answers:
fomenos3 years ago
8 0

Answer:

B is the answers for the question

Step-by-step explanation:

please mark me as brainlest

dezoksy [38]3 years ago
7 0

Answer:

alternat interior angle

Step-by-step explanation:

plz mark me brainlists plz and plz

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Answer:И тхинк 0

Step-by-step explanation:

5 0
3 years ago
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There are 8 times as many females as males on the maths course at university. What fraction of the course are female?
Tcecarenko [31]

Answer:

Step-by-step explanation:

Let the males = x

Let the females = 8x

Let the total in the class = x + 8x = 9x

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4 0
3 years ago
a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
3 years ago
Show me how to do this on paper i need it right now
postnew [5]

Answer:

Step-by-step explanation:

32 x 10 = 320

32 x 4 = 128

320 + 128 = 448

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