2cos²x+cos x-1=0
cos x=t
2t²+t-1=0
t=[-1⁺₋√(-1+8)]/2=(-1⁺₋3)/4
We have two possible set solutions:
First set solutions.
t₁=(-1-3)/2=-4/4=-1
cos x=-1 ⇒x=cos⁻¹ (-1)=π +2kπ or 180º+360ºk (k=(...-2,-1,0,1,2...)
Second set solutions:
t₂=(-1+3)/4=2/4=1/2
cos x=1/2 ⇒ x=cos⁻¹ 1/2=π/3+2kπ U 5π/3+ 2kπ or
60º+360ºK U 300º+360ºK (k=...-2,-1,0,1,2,...)
solutions: first set solutions U second set solutions:
Answer in radians : π +2kπ U π/3+2kπ U 5π/3+ 2kπ (k=...-1,0,1,...)
Answer is degrees: 180º+360ºk U 60º+360ºK U 300º+360ºK (k=...-2,-1,0,1,2,...)
Using concepts of the normal and of the uniform distribution, it is found that the correct option is:
The distribution is approximately Normal, with a mean of 8 ounces and a standard deviation of 1.2 ounces.
- In an uniform distribution, all outcomes are equally as likely, thus they have the same height.
- In the normal distribution, the outcomes with the highest likelihood are those closest to the mean, thus they have the highest height. This means that the mean of this distribution is 8.
- The standard deviation cannot be a negative value, so in this problem, it is 1.2, which means that the correct option is:
The distribution is approximately Normal, with a mean of 8 ounces and a standard deviation of 1.2 ounces.
A similar problem is given at brainly.com/question/25128186
Answer:
(h + g)(10) = -6
Step-by-step explanation:
Step 1: Define
h(x) = 3x + 3
g(x) = -4x + 1
Step 2: Find (h + g)(x)
(h + g)(x) = 3x + 3 + -4x + 1
(h + g)(x) = -x + 4
Step 3: Substitute and Evaluate
(h + g)(10) = -10 + 4
(h + g)(10) = -6
Answer:Q1–1.5 •IQR
Step-by-step explanation: i just took the assignment
1. arithmetic, arithmetic, geometric
2. 3, 6, 9, 12, 15
3. -7n + 5
4. 2.4
5. 45
6. 4n + 137
